Single-Photon Atomic Cooling - Raizen Lab - The University of ...
Single-Photon Atomic Cooling - Raizen Lab - The University of ...
Single-Photon Atomic Cooling - Raizen Lab - The University of ...
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Eq. 2.4 yields<br />
J 2 = S 2 + L 2 + 2 L · S, (2.6)<br />
allowing us to rewrite the fine structure Hamiltonian (Eq. 2.3) as<br />
Hfs = A<br />
2 (J2 − S 2 − L 2 ). (2.7)<br />
Because the energy shift <strong>of</strong> this Hamiltonian is small compared to the<br />
Bohr splittings, it can be introduced as a perturbation to those energy levels.<br />
Time independent perturbation theory allows us to write the shift in an energy<br />
level to first order due to this perturbation as<br />
∆E = 〈Ψ|Hfs|Ψ〉. (2.8)<br />
This notation introduces the question <strong>of</strong> what basis should be taken to make<br />
the evaluation <strong>of</strong> this matrix element the simplest. <strong>The</strong> coupling <strong>of</strong> L and<br />
S has caused Lz and Sz to be unconserved quantities so the uncoupled basis<br />
|L,Lz,S,Sz〉 is clearly not an eigenvector <strong>of</strong> Eq. 2.7. However, from inspection<br />
it is clear that elements <strong>of</strong> the coupled basis |S,L,J,Jz〉 are eigenvectors <strong>of</strong> the<br />
fine structure Hamiltonian and can be used to evaluate Eq. 2.7, immediately<br />
resulting in<br />
∆E = A2<br />
[J(J + 1) − S(S + 1) − L(L + 1)]. (2.9)<br />
2<br />
<strong>The</strong> ground state configuration <strong>of</strong> 87 Rb is [Kr]5s. This means that<br />
there is one unpaired electron and that this electron has no orbital angular<br />
momentum, therefore S = 1/2 and L = 0. This means that the only value J<br />
can take is J = 1/2. Evidently, the ground state is not split by Hfs because<br />
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