Experiments to Control Atom Number and Phase-Space Density in ...
Experiments to Control Atom Number and Phase-Space Density in ...
Experiments to Control Atom Number and Phase-Space Density in ...
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where<br />
is used.<br />
ˆǫ ′ <strong>in</strong>c ·ˆǫ ∗ 1 = 1 √ (ˆx<br />
2 ′ ∓iˆy ′ )· ˆx ′ = 1<br />
√<br />
2<br />
ˆǫ ′ <strong>in</strong>c ·ˆǫ ∗ 2 = 1 √ (ˆx<br />
2 ′ ∓iˆy ′ )· ˆy ′ = ∓ i<br />
√<br />
2<br />
The scattered field is then found by subtract<strong>in</strong>g the <strong>in</strong>cident field:<br />
Escat = Eobj −E<strong>in</strong>c<br />
= E0<br />
<br />
−nξ1σ0<br />
√2 exp<br />
2(1+δ 2 <br />
(1+iδ) ˆǫ1 ∓<br />
)<br />
iE0<br />
<br />
√2 ˆǫ2 −<br />
= E0<br />
<br />
−nξ1σ0<br />
√2 exp<br />
2(1+δ 2 <br />
(1+iδ) −1 ˆǫ1<br />
)<br />
1<br />
E0√<br />
(ˆǫ<br />
2 ′ 1 ∓iˆǫ ′ 2)<br />
<br />
(7.21)<br />
(7.22)<br />
(7.23)<br />
To derive the <strong>in</strong>tensity profile <strong>in</strong> the imag<strong>in</strong>g plane, the effect of the imag<strong>in</strong>g optics on<br />
the fields has <strong>to</strong> be taken <strong>in</strong><strong>to</strong> account. In the th<strong>in</strong> lens approximation [110] the scattered<br />
<strong>and</strong> <strong>in</strong>cident fields are thus given by<br />
Escat(x ′ ,y ′ ) = E0<br />
<br />
−nξ1σ0<br />
√2 exp<br />
2(1+δ 2 <br />
ik<br />
(1+iδ) −1 exp<br />
)<br />
<br />
<br />
ik<br />
E<strong>in</strong>c = E0 exp<br />
= E0 exp<br />
2f (x′2 +y ′2 )<br />
ik<br />
2f (x′2 +y ′2 )<br />
ˆǫ ′ <strong>in</strong>c = E0 exp<br />
1<br />
<br />
ˆǫ1 (7.24)<br />
2f (x′2 +y ′2 )<br />
<br />
ik<br />
2f (x′2 +y ′2 <br />
1√2<br />
) (ˆǫ ′ 1 ∓iˆǫ ′ 2)<br />
√2 (ˆx ′ ±iˆy ′ ). (7.25)<br />
The <strong>to</strong>tal electric field <strong>in</strong> the image plane is determ<strong>in</strong>ed by the sum of the scat-<br />
tered <strong>and</strong> the <strong>in</strong>cident field:<br />
E<strong>to</strong>t = Escat +E<strong>in</strong>c<br />
= E0<br />
<br />
−nξ1σ0<br />
√2 exp<br />
2(1+δ 2 <br />
ik<br />
(1+iδ) −1 exp<br />
)<br />
<br />
ik<br />
E0 exp<br />
2f (x′2 +y ′2 <br />
1√2<br />
) (ˆǫ ′ 1 ∓iˆǫ ′ 2)<br />
= E0<br />
1 −n2 √2 exp<br />
σ0<br />
2(1+δ 2 <br />
ik<br />
(1+iδ) −1 exp<br />
)<br />
<br />
1√2<br />
E0 exp (ˆx ′ ±iˆy ′ )<br />
ik<br />
2f (x′2 +y ′2 )<br />
145<br />
2f (x′2 +y ′2 )<br />
2f (x′2 +y ′2 )<br />
<br />
ˆǫ1 +<br />
<br />
ˆx ′ +