SP - 5
SP - 5
SP - 5
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Statically indeterminate rod<br />
(Strength of Materials - I, Mid-term Exam-44-5)<br />
Problem :<br />
Two cylindrical rods, CD made of steel (E = 29 × 10 6 psi) and AC made of aluminum<br />
(E = 10.4 × 10 6 psi), are joined at C and restrained by rigid supports at A and D.<br />
Determine (a) the reactions at A and D, (b) the deflection of point C. (1 kips = 1000 lb)<br />
Solution :<br />
Internal forces<br />
F1 = RA<br />
F2 = RA − 18000<br />
F3 = RA − 32000<br />
The compatibility relation of deformation<br />
∆ε1 + ∆ε2 + ∆ε3 = 0<br />
<br />
<br />
<br />
l<br />
l<br />
l<br />
RA + (RA − 18000) + (RA − 32000) = 0<br />
AE 1<br />
AE 2<br />
AE 3<br />
The cross-sectional areas<br />
A1 = A2 = π<br />
4<br />
A3 = π<br />
<br />
1<br />
4<br />
5<br />
8<br />
<br />
1 1<br />
8<br />
2<br />
2<br />
= 0.994 02 mm 2<br />
= 2. 073 9 mm 2<br />
1<br />
0.994 02 × 10.4 × 106 (8RA<br />
10<br />
+ 10 (RA − 18000)) + (RA − 32000)<br />
= 0<br />
2. 073 9 × 29 × 106 Prof. Dr. M. Kemal APALAK 1
The deflection of the point C<br />
18RA − 18 × 10 4 + (RA − 32000) × 1.71875 = 0<br />
19. 719RA = 2. 35 × 10 5<br />
RA = 11917 lb<br />
RA + RD = 32000<br />
RD = 32000 − 11917<br />
RD = 20083 lb<br />
∆ε3 =<br />
<br />
l<br />
10<br />
δC = RD = 20083 ×<br />
AE 3<br />
2. 073 9 × 29 × 106 ∆ε3 = δC = 3. 339 2 × 10 −3 in (→)<br />
Prof. Dr. M. Kemal APALAK 2