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A Game-Theoretic Approach to Personnel Decisions in American ...

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δ<br />

1<br />

0.9<br />

0.8<br />

0.7<br />

0.6<br />

0.5<br />

0.4<br />

0.3<br />

0.2<br />

0.1<br />

R* Color<strong>in</strong>g the Unit Square<br />

0<br />

0 0.2 0.4 0.6 0.8 1<br />

x<br />

Figure 1: R ∗ (δ,x) us<strong>in</strong>g 2008 Chicago Bears Data<br />

As can be seen <strong>in</strong> Figure 1, the break<strong>in</strong>g po<strong>in</strong>t when δ = 1 (as <strong>in</strong> 2<br />

our calculations) is approximately 0.775. This implies that <strong>to</strong> be justified<br />

<strong>in</strong> play<strong>in</strong>g a pure pass strategy, the expected yards per play would have <strong>to</strong><br />

<strong>in</strong>crease by approximately 2.178 yards. This is a large <strong>in</strong>crease, and supports<br />

our claim that it is unrealistic <strong>to</strong> anticipate that Chicago would ever pursue a<br />

pure pass<strong>in</strong>g strategy.<br />

In order <strong>to</strong> exam<strong>in</strong>e how Jay Cutler impacts the run/pass balance of<br />

the Chicago Bears, we first f<strong>in</strong>d his x. To do so, we will consider Cutler’s<br />

effect on the Broncos’ offense <strong>in</strong> 2007, his first year as a starter. We beg<strong>in</strong><br />

us<strong>in</strong>g the data from the 2006 Broncos offense <strong>to</strong> calculate Table 6, Denver’s<br />

2007 improvement <strong>in</strong> pass<strong>in</strong>g model, <strong>in</strong> a manner similar <strong>to</strong> our development<br />

of Table 4.<br />

Defense<br />

Defend Run Defend Pass<br />

Offense Run 2.73(1 + δx) 4.25(1 + δx)<br />

Pass 4.86(1 + x) 3.33(1 + x)<br />

Table 6: The 2007 Denver Broncos Improvement <strong>in</strong> Pass<strong>in</strong>g Model<br />

In 2007, the Broncos ga<strong>in</strong>ed an average of 4.57 yards per play. Thus,<br />

the x-value that we seek for Jay Cutler is the solution <strong>to</strong> V ∗ ( 1,x)<br />

= 4.57,<br />

2<br />

where V ∗ is as given <strong>in</strong> (7). Solv<strong>in</strong>g, we obta<strong>in</strong> x ≈ 0.279.<br />

1<br />

0.9<br />

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0.1<br />

0

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