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"Chapter 1 - The Op Amp's Place in the World" - HTL Wien 10

"Chapter 1 - The Op Amp's Place in the World" - HTL Wien 10

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<strong>The</strong> Invert<strong>in</strong>g <strong>Op</strong> Amp<br />

3-4<br />

<strong>in</strong> a current feedback amplifier design because R F determ<strong>in</strong>es stability <strong>in</strong> current feedback<br />

amplifiers.<br />

Notice that <strong>the</strong> ga<strong>in</strong> is only a function of <strong>the</strong> feedback and ga<strong>in</strong> resistors; <strong>the</strong>refore <strong>the</strong><br />

feedback has accomplished its function of mak<strong>in</strong>g <strong>the</strong> ga<strong>in</strong> <strong>in</strong>dependent of <strong>the</strong> op amp<br />

parameters. <strong>The</strong> ga<strong>in</strong> is adjusted by vary<strong>in</strong>g <strong>the</strong> ratio of <strong>the</strong> resistors. <strong>The</strong> actual resistor<br />

values are determ<strong>in</strong>ed by <strong>the</strong> impedance levels that <strong>the</strong> designer wants to establish.<br />

If R F = <strong>10</strong> k and R G = <strong>10</strong> k <strong>the</strong> ga<strong>in</strong> is two as shown <strong>in</strong> Equation 2, and if R F = <strong>10</strong>0 k and<br />

R G = <strong>10</strong>0 k <strong>the</strong> ga<strong>in</strong> is still two. <strong>The</strong> impedance levels of <strong>10</strong> k or <strong>10</strong>0 k determ<strong>in</strong>e <strong>the</strong> current<br />

dra<strong>in</strong>, <strong>the</strong> effect of stray capacitance, and a few o<strong>the</strong>r po<strong>in</strong>ts. <strong>The</strong> impedance level<br />

does not set <strong>the</strong> ga<strong>in</strong>; <strong>the</strong> ratio of R F/R G does.<br />

3.3 <strong>The</strong> Invert<strong>in</strong>g <strong>Op</strong> Amp<br />

<strong>The</strong> non<strong>in</strong>vert<strong>in</strong>g <strong>in</strong>put of <strong>the</strong> <strong>in</strong>vert<strong>in</strong>g op amp circuit is grounded. One assumption made<br />

is that <strong>the</strong> <strong>in</strong>put error voltage is zero, so <strong>the</strong> feedback keeps <strong>in</strong>vert<strong>in</strong>g <strong>the</strong> <strong>in</strong>put of <strong>the</strong> op<br />

amp at a virtual ground (not actual ground but act<strong>in</strong>g like ground). <strong>The</strong> current flow <strong>in</strong> <strong>the</strong><br />

<strong>in</strong>put leads is assumed to be zero, hence <strong>the</strong> current flow<strong>in</strong>g through R G equals <strong>the</strong> current<br />

flow<strong>in</strong>g through R F. Us<strong>in</strong>g Kirchoff’s law, we write Equation 3–4; and <strong>the</strong> m<strong>in</strong>us sign<br />

is <strong>in</strong>serted because this is <strong>the</strong> <strong>in</strong>vert<strong>in</strong>g <strong>in</strong>put. Algebraic manipulation gives Equation 3–5.<br />

VIN<br />

Figure 3–3. <strong>The</strong> Invert<strong>in</strong>g <strong>Op</strong> Amp<br />

I1<br />

RG IB = 0<br />

IB = 0<br />

VE<br />

I1 VIN I<br />

R 2 <br />

G<br />

VOUT RF V OUT<br />

V IN<br />

R F<br />

R G<br />

I2<br />

_<br />

a<br />

+<br />

RF<br />

VOUT<br />

(3–4)<br />

(3–5)<br />

Notice that <strong>the</strong> ga<strong>in</strong> is only a function of <strong>the</strong> feedback and ga<strong>in</strong> resistors, so <strong>the</strong> feedback<br />

has accomplished its function of mak<strong>in</strong>g <strong>the</strong> ga<strong>in</strong> <strong>in</strong>dependent of <strong>the</strong> op amp parameters.<br />

<strong>The</strong> actual resistor values are determ<strong>in</strong>ed by <strong>the</strong> impedance levels that <strong>the</strong> designer<br />

wants to establish. If R F = <strong>10</strong> k and R G = <strong>10</strong> k <strong>the</strong> ga<strong>in</strong> is m<strong>in</strong>us one as shown <strong>in</strong> Equation

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