HW4 Solution
HW4 Solution HW4 Solution
, , As stated in part (b), the maximum velocity corresponding to this maximum power will be determined graphically. Numerical Substitution: To find the power required at sea level, it is required to know the air density at sea level. From Appendix B, the sea level standard air density is 0.0023769 Using the required power equation and the maximum and minimum power equations, the following graph was produced: Power Required [HP] 400 350 300 250 200 150 100 50 0 Sea Level Power Required vs. Velocity 0 50 100 150 200 250 300 350 Velocity [ft/s] Power Required Maximum Velocity Minimum Power For part (a), acceptable answers for required power lie on the “Power Required” curve. To find the minimum power, the velocity at minimum power equation is used. 43000 30.91 6.20.027 0.0023769 181 220 192.5 165 137.5 110 82.5 55 27.5 0 Power Required [1000 lbf * ft/s]
36000000 0.26573 36000000 0.26573 36000000 0.26573 107.9 As can be seen, this result for agrees with the “Sea Level Power Required vs. Velocity” graph. Using this velocity, the minimum power required is given by, 1 0.0023769 107.9 2 1810.027 23000 0.0023769 107.9 1810.91 6.2 · 7296 21877 · 7296 · 21877 · · 29173 · The required power can also be represented in hp as follows: 29173 · 53.04 hp 1 hp 550 · As can be seen, this result for agrees with the “Sea Level Power Required vs. Velocity” graph. This concludes that answer to part (a). In part (b), it is required to find the maximum velocity. To do so, it is first necessary to find the maximum power available. 0.83345 hp 286.35 hp Using the graph, this maximum power at sea level corresponds to
- Page 1 and 2: Zachary Lovering Nov. 7, 2008 MAE 2
- Page 3 and 4: Problem 6.2 Description: An airplan
- Page 6 and 7: Problem 6.4 Description: Consider a
- Page 10 and 11: 295 This value is represented by
- Page 12 and 13: Problem 6.25 Description: The Preda
- Page 14: To solve this equation iteratively,
36000000 <br />
0.26573 <br />
<br />
36000000<br />
0.26573<br />
36000000<br />
0.26573<br />
107.9 <br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
As can be seen, this result for agrees with the “Sea Level Power Required vs. Velocity” graph. Using this<br />
velocity, the minimum power required is given by,<br />
<br />
<br />
1<br />
<br />
0.0023769 107.9<br />
2 <br />
<br />
1810.027 23000 <br />
<br />
<br />
0.0023769 <br />
107.9<br />
1810.91 6.2<br />
· <br />
7296<br />
<br />
21877 · <br />
<br />
7296 · <br />
21877 · <br />
· <br />
29173 · <br />
<br />
The required power can also be represented in hp as follows:<br />
29173 · <br />
<br />
53.04 hp<br />
<br />
1 hp<br />
550 · <br />
<br />
As can be seen, this result for agrees with the “Sea Level Power Required vs. Velocity” graph. This concludes<br />
that answer to part (a). In part (b), it is required to find the maximum velocity. To do so, it is first necessary to<br />
find the maximum power available.<br />
0.83345 hp<br />
286.35 hp<br />
Using the graph, this maximum power at sea level corresponds to
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