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HW4 Solution

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1.2250 <br />

<br />

Additionally, must be represented in consistent units,<br />

350 <br />

1000<br />

1<br />

<br />

1 3600 <br />

97.2 <br />

<br />

Using the equation derived in the analysis, the required thrust is given by,<br />

Note that,<br />

1 <br />

1.2250<br />

2 97.2<br />

<br />

<br />

· <br />

<br />

4739.4 436.04<br />

· <br />

5175.4 <br />

27.3 0.03 <br />

1 1<br />

238220 <br />

1.2250 <br />

97.2<br />

27.30.97.5 · <br />

<br />

For part (b), it is first necessary to find the air density at 4.5 . From Appendix A,<br />

0.77704 <br />

<br />

Using the equation derived in the analysis, the required thrust is given by,<br />

1<br />

<br />

0.77704<br />

2 97.2<br />

<br />

<br />

· <br />

<br />

3006.3 687.42<br />

· <br />

3693.7 <br />

27.3 0.03 <br />

238220 <br />

0.77704 <br />

97.2<br />

27.30.97.5

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