HW4 Solution

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295 This value is represented by the “maximum velocity” line on the graph. For part (c), a new plot can be created to adjust for the density difference at 12000 altitude. The air density at 12000 can be found in Appendix B. 0.0016480 Answers for required power lie on the “Power Required” curve in the graph below. Power Required [HP] 300 250 200 150 100 50 0 12,000 ft Altitude Power Required vs. Velocity 0 50 100 150 200 250 300 350 Velocity [ft/s] Maximum Power Maximum Velocity Minimum Power The minimum power required can be solved as in part (a) or can be solved graphically. Additionally, the density change can be accounted for as follows: 0.0023769 0.0016480 107.9 1.201 129.6 107.9 Similarly, the corresponding minimum power at altitude is, 165 137.5 110 82.5 55 27.5 0 Power Required [1000 lbf * ft/s]
, 29173 · 35035 · 0.0023769 0.0016480 63.70 hp Since the engine output power is proportional to the air density, the power available must also be adjusted. 0.0016480 , 286.35 hp 0.0023769 , 286.35 hp0.6933 , 198.54 hp Using the graph, this maximum power at 12000 corresponds to 289
Page 1 and 2: Zachary Lovering Nov. 7, 2008 MAE 2
Page 3 and 4: Problem 6.2 Description: An airplan
Page 6 and 7: Problem 6.4 Description: Consider a
Page 8 and 9: , , As stated in part (b), the
Page 12 and 13: Problem 6.25 Description: The Preda
Page 14: To solve this equation iteratively,

HW4 Solution

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