3+1 formalism and bases of numerical relativity - LUTh ...
3+1 formalism and bases of numerical relativity - LUTh ...
3+1 formalism and bases of numerical relativity - LUTh ...
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94 Conformal decomposition<br />
to write<br />
<br />
∂<br />
− Lβ ˜γij = −2N<br />
∂t Ãij − 2<br />
3 ˜ Dkβ k ˜γij . (6.73)<br />
Notice that, as an immediate consequence <strong>of</strong> Eq. (6.54), Ãij is traceless:<br />
Let us rise the indices <strong>of</strong> Ãij with the conformal metric, defining<br />
Since ˜γ ij = Ψ 4 γ ij , we get<br />
˜γ ij Ãij = 0 . (6.74)<br />
à ij := ˜γ ik ˜γ jl Ãkl. (6.75)<br />
à ij = Ψ 4 A ij . (6.76)<br />
This corresponds to the scaling factor α = −4 in Eq. (6.58). This choice <strong>of</strong> scaling has been first<br />
considered by Nakamura in 1994 [192].<br />
We can deduce from Eq. (6.73) an evolution equation for the inverse conformal metric ˜γ ij .<br />
Indeed, raising the indices <strong>of</strong> Eq. (6.73) with ˜γ, we get<br />
hence<br />
˜γ ik ˜γ jl Lm ˜γkl = −2N Ãij − 2<br />
3 ˜ Dkβ k ˜γ ij<br />
˜γ ik [Lm(˜γ jl ˜γkl ) − ˜γklLm ˜γ jl ] = −2NÃij − 2<br />
3 ˜ Dkβ k ˜γ ij<br />
<br />
=δ j<br />
k<br />
− ˜γ ik ˜γkl<br />
<br />
=δ i l<br />
2) “Momentum-constraint” scaling: α = −10<br />
Lm ˜γ jl = −2N Ãij − 2<br />
3 ˜ Dkβ k ˜γ ij , (6.77)<br />
<br />
∂<br />
− Lβ ˜γ<br />
∂t ij = 2NÃij + 2<br />
3 ˜ Dkβ k ˜γ ij . (6.78)<br />
Whereas the scaling α = −4 was suggested by the evolution equation (6.59) (or equivalently<br />
Eq. (4.63) <strong>of</strong> the <strong>3+1</strong> Einstein system), another scaling arises when contemplating the momentum<br />
constraint equation (4.66). In this equation appears the divergence <strong>of</strong> the extrinsic<br />
curvature, that we can write using the twice contravariant version <strong>of</strong> K <strong>and</strong> Eq. (6.57):<br />
Now, from Eqs. (6.29), (6.33) <strong>and</strong> (6.46),<br />
DjK ij = DjA ij + 1<br />
3 Di K. (6.79)<br />
DjA ij = ˜ DjA ij + C i jkAkj + C j<br />
jkAik = ˜ DjA ij <br />
+ 2 δ i j ˜ Dk ln Ψ + δ i k ˜ Dj ln Ψ − ˜ D i ln Ψ ˜γjk<br />
<br />
A kj + 6 ˜ Dk ln Ψ A ik<br />
= ˜ DjA ij + 10A ij ˜ Dj lnΨ − 2 ˜ D i ln Ψ ˜γjkA jk . (6.80)