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3+1 formalism and bases of numerical relativity - LUTh ...

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74 <strong>3+1</strong> equations for matter <strong>and</strong> electromagnetic field<br />

Let us denote by D the Levi-Civita connection associated with the flat metric f. Obviously<br />

DΦ = DΦ. On the other side, let us express the divergence D · p in terms <strong>of</strong> the divergence<br />

D · p. From Eq. (5.15), we have γ ij = (1 − 2Φ) −1 f ij ≃ (1 + 2Φ)f ij as well as the relation<br />

√ γ = (1 − 2Φ) 3 f ≃ (1 − 3Φ) √ f between the determinants γ <strong>and</strong> f <strong>of</strong> respectively (γij) <strong>and</strong><br />

(fij). Therefore<br />

D · p = 1<br />

√ γ<br />

∂<br />

∂xi √ i<br />

γp = 1<br />

√<br />

γ<br />

∂<br />

∂xi √ ij<br />

γγ pj<br />

≃<br />

1<br />

(1 − 3Φ) √ ∂<br />

f ∂xi <br />

(1 − 3Φ) f(1 + 2Φ)f ij <br />

pj ≃ 1 ∂<br />

√<br />

f ∂xi <br />

(1 − Φ) ff ij ≃<br />

<br />

pj<br />

1 ∂<br />

√<br />

f ∂xi <br />

ij<br />

ff pj − f ij ∂Φ<br />

pj<br />

∂xi ≃ D · p − p · DΦ. (5.17)<br />

Consequently Eq. (5.16) becomes<br />

∂E<br />

∂t<br />

+ D · p = −p · DΦ. (5.18)<br />

This is the st<strong>and</strong>ard energy conservation relation in a Galilean frame with the source term<br />

−p·DΦ. The latter constitutes the density <strong>of</strong> power provided to the system by the gravitational<br />

field (this will be clear in the perfect fluid case, to be discussed below).<br />

Remark : In the left-h<strong>and</strong> side <strong>of</strong> Eq. (5.18), the quantity p plays the role <strong>of</strong> an energy flux,<br />

whereas it had been defined in Sec. 4.1.2 as a momentum density. It is well known that<br />

both aspects are equivalent (see e.g. Chap. 22 <strong>of</strong> [155]).<br />

5.2.4 Momentum conservation<br />

Let us now project Eq. (5.2) onto Σt:<br />

Now, from relation (2.79),<br />

Besides<br />

γ ν α ∇µS µ ν − Kpα + γ ν α nµ ∇µpν − Kαµp µ + EDα ln N = 0. (5.19)<br />

DµS µ α = γ ρ µγ µ σγ ν α∇ρS σ ν = γ ρ σγ ν α∇ρS σ ν<br />

= γ ν α(δ ρ σ + n ρ nσ)∇ρS σ ν = γ ν α(∇ρS ρ ν − S σ ν n ρ ∇ρnσ )<br />

<br />

=Dσ ln N<br />

= γ ν α∇µS µ ν − S µ αDµ ln N. (5.20)<br />

γ ν α nµ ∇µpν = N −1 γ ν α mµ ∇µpν = N −1 γ ν α (Lmpν − pµ∇νm µ )<br />

= N −1 Lmpα + Kαµp µ , (5.21)

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