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3+1 formalism and bases of numerical relativity - LUTh ...

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8.2 Conformal transverse-traceless method 137<br />

where r := x2 + y2 + z2 , ǫ ij<br />

k is the Levi-Civita alternating tensor associated with the flat<br />

metric f <strong>and</strong> (Pi,Sj) = (P1,P2,P3,S1,S2,S3) are six real numbers, which constitute the six<br />

parameters <strong>of</strong> the Bowen-York solution. Notice that since r = 0 on Σ0, the Bowen-York solution<br />

is a regular <strong>and</strong> smooth solution on the entire Σ0.<br />

Example : Choosing Pi = (0,P,0) <strong>and</strong> Si = (0,0,S), where P <strong>and</strong> S are two real numbers,<br />

leads to the following expression <strong>of</strong> the Bowen-York solution:<br />

⎧<br />

⎪⎨<br />

⎪⎩<br />

Xx = − P xy y<br />

+ S<br />

4 r3 r3 Xy = − P<br />

<br />

7 +<br />

4r<br />

y2<br />

r2 <br />

− S x<br />

r3 Xz = − P xz<br />

4 r3 (8.70)<br />

The conformal traceless extrinsic curvature corresponding to the solution (8.69) is deduced from<br />

formula (8.9), which in the present case reduces to Âij = (LX) ij ; one gets<br />

 ij = 3<br />

2r3 <br />

x i P j + x j P i <br />

− f ij − xixj r2 <br />

Pkx k<br />

<br />

+ 3<br />

r5 <br />

ǫ ik lSkx l x j + ǫ jk<br />

lSkx l x i<br />

, (8.71)<br />

where P i := f ij Pj. The tensor Âij given by Eq. (8.71) is called the Bowen-York extrinsic<br />

curvature. Notice that the Pi part <strong>of</strong> Âij decays asymptotically as O(r −2 ), whereas the Si<br />

part decays as O(r −3 ).<br />

Remark : Actually the expression <strong>of</strong> Âij given in the original Bowen-York article [65] contains<br />

an additional term with respect to Eq. (8.71), but the role <strong>of</strong> this extra term is only to<br />

ensure that the solution is isometric through an inversion across some sphere. We are<br />

not interested by such a property here, so we have dropped this term. Therefore, strictly<br />

speaking, we should name expression (8.71) the simplified Bowen-York extrinsic curvature.<br />

Example : Choosing Pi = (0,P,0) <strong>and</strong> Si = (0,0,S) as in the previous example [Eq. (8.70)],<br />

we get<br />

 xx = − 3P<br />

2r3y <br />

1 − x2<br />

r2 <br />

− 6S<br />

Â<br />

xy<br />

r5 (8.72)<br />

xy = 3P<br />

2r3x <br />

1 + y2<br />

r2 <br />

+ 3S<br />

r5 (x2 − y 2 ) (8.73)<br />

 xz = 3P<br />

Â<br />

3S<br />

2r5xyz − yz<br />

r5 (8.74)<br />

yy = 3P<br />

2r3y <br />

1 + y2<br />

r2 <br />

+ 6S<br />

Â<br />

xy<br />

r5 (8.75)<br />

yz = 3P<br />

2r3z <br />

1 + y2<br />

r2 <br />

+ 3S<br />

Â<br />

xz<br />

r5 (8.76)<br />

zz = − 3P<br />

2r3y <br />

1 − z2<br />

r2 <br />

. (8.77)

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