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3+1 formalism and bases of numerical relativity - LUTh ...

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136 The initial data problem<br />

Figure 8.4: Extended hypersurface Σ ′ 0 depicted in the Kruskal-Szekeres representation <strong>of</strong> Schwarzschild spacetime.<br />

R st<strong>and</strong>s for Schwarzschild radial coordinate <strong>and</strong> r for the isotropic radial coordinate. R = 0 is the singularity<br />

<strong>and</strong> R = 2m the event horizon. Σ ′ 0 is nothing but a hypersurface t = const, where t is the Schwarzschild time<br />

coordinate. In this diagram, these hypersurfaces are straight lines <strong>and</strong> the Einstein-Rosen bridge S is reduced to<br />

a point.<br />

8.2.6 Bowen-York initial data<br />

Let us select the same simple free data as above, namely<br />

˜γij = fij, Â ij<br />

TT = 0, K = 0, ˜ E = 0 <strong>and</strong> ˜p i = 0. (8.67)<br />

For the hypersurface Σ0, instead <strong>of</strong> R 3 minus a ball, we choose R 3 minus a point:<br />

Σ0 = R 3 \{O}. (8.68)<br />

The removed point O is called a puncture [66]. The topology <strong>of</strong> Σ0 is S2 × R; it differs from<br />

the topology considered in Sec. 8.2.5 (R3 minus a ball); actually it is the same topology as that<br />

(cf. Fig. 8.3).<br />

<strong>of</strong> the extended manifold Σ ′ 0<br />

Thanks to the choice (8.67), the system to be solved is still (8.39)-(8.40). If we choose<br />

the trivial solution X = 0 for Eq. (8.40), we are back to the slice <strong>of</strong> Schwarzschild spacetime<br />

considered in Sec. 8.2.5, except that now Σ0 is the extended manifold previously denoted Σ ′ 0 .<br />

Bowen <strong>and</strong> York [65] have obtained a simple non-trivial solution <strong>of</strong> Eq. (8.40) (see also<br />

Ref. [49]). Given a Cartesian coordinate system (xi ) = (x,y,z) on Σ0 (i.e. a coordinate system<br />

such that fij = diag(1,1,1)) with respect to which the coordinates <strong>of</strong> the puncture O are (0,0,0),<br />

this solution writes<br />

X i = − 1<br />

<br />

7f<br />

4r<br />

ij Pj + Pjxjxi r2 <br />

− 1<br />

r3ǫij kSjx k , (8.69)

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