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SENSORLESS FIELD ORIENTED CONTROL OF BRUSHLESS ...

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3<br />

v v v v v v v<br />

AM BM CM AM BM BM ZS<br />

3<br />

v v v v<br />

(D.13)<br />

AM BM CM ZS<br />

The currents in the load must sum to zero. Since there are no voltage sources in the load, the sum<br />

of the line-neutral load voltages must also sum to zero (Equation D.14).<br />

Z s IA s IB s IC s <br />

V s V s V s <br />

() () () () 0<br />

() () () 0<br />

AN BN CN<br />

v v v 0<br />

(D.14)<br />

AN BN CN<br />

Applying the results of Equations (D.13)-(D.14) to Equation (D.11) gives Equation (D.15).<br />

<br />

3v 0 3v<br />

ZS NM<br />

vNM vZS<br />

(D.15)<br />

Thus the ZS component of source voltage will always appear at the neutral in a passive load with<br />

an isolated neutral. That v NM is a common-mode voltage should have already been clear from<br />

Equation (D.10) and that the neutral voltage is exactly the common-mode voltage should be clear<br />

from a general knowledge of circuit theory. To emphasize the latter, examine Figure D.5 in light<br />

of Equation (D.12). There is no difference between the two circuits in Figure D.5 and it is seen<br />

that the “balanced portion” of the source is v ZS above ground.<br />

Figure D.5 – Equivalent source showing that ZS is common-mode.<br />

By using Equation (D.15) the same perspective can be used to examine the load, as shown in<br />

Figure D.6. The voltage v ZS is drawn as a square because it is not a real source (just as the point<br />

of zero potential does not physically exist); the v ZS voltage against the zero potential simply<br />

represents the effect of v ZS on the load; no current can be driven through it.<br />

314

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