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SENSORLESS FIELD ORIENTED CONTROL OF BRUSHLESS ...

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Figure 4.26 – Base SVs showing the states of a 180° inverter.<br />

The values in Table 4.2 are for k 2/3 such that they will be magnitude invariant. Since the<br />

values in Table 4.2 were computed from the voltages in Table 4.1 (which were peak line-neutral<br />

<br />

voltages specified in terms of V DC ), the SVs have magnitude Si(4 / 3) VDC.<br />

Now compare<br />

<br />

Figure 4.26 with Figure 4.23. For state S1, S1<br />

has a magnitude of S (4 / 3) V<br />

i DC<br />

and it is seen<br />

that the phase-neutral voltage of phase-A has the same magnitude. This seems to make sense<br />

because k 2/3 yields a magnitude-invariant SV. But the values in Table 4.2 (hence the<br />

magnitude of the SVs in Figure 4.26) were computed from the pole voltages in Table 4.1, not the<br />

phase voltages. Why then do the SV magnitudes match the phase voltages? The reason is that the<br />

SV (the α- and β- components) cannot contain a ZS component. By definition (Equation 4.5 and<br />

Appendix D) each pole voltage is composed of a phase voltage (which cannot contain a ZS<br />

component) and the neutral voltage (which consists of only the ZS component). Since the SV can<br />

only contain the non-ZS component, taking the SV transform of the pole voltages produces the<br />

same result as taking the SV transform of the phase voltages; in either case, the resulting SV will<br />

represent the phase voltages. Since the only difference is the ZS term, we should be able to see<br />

this using the αβ0 transform. The αβ0 transform of the pole voltages were given as Table 4.2; the<br />

ZS terms are clearly present. Now the αβ0 transform of the phase voltages is given below in<br />

183

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