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SENSORLESS FIELD ORIENTED CONTROL OF BRUSHLESS ...

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in relative time like an oscillograph. Each sweep in an oscilloscope will the trigger on the same<br />

point in the periodic waveform and for the phasor diagram that trigger point is the peak of the<br />

reference signal. In contrast, SV diagrams are drawn with reference to the phase axes (or<br />

real/imaginary axes). For illustration two SVs are defined by Equations (3.121) and (3.122).<br />

These are shown on a SV diagram (Figure 3.40) for arbitrary values ωt=30° and δ=15°.<br />

ˆ j1 x1 Xe 1<br />

jt X p1e<br />

(3.121)<br />

<br />

x ˆ j2 X e<br />

jt X e<br />

(3.122)<br />

2 2 p1<br />

Figure 3.40 – Space vector diagram.<br />

It is useful and appropriate to show the instantaneous SV relative to the phase axes for some<br />

value of ωt (such Figure 3.26) when showing the position of the SV at a particular instant. But<br />

often the steady-state SV diagram will be drawn at t 0 and the SV diagram will look like<br />

exactly like a phasor diagram. Comparing Equations (3.119)-(3.120) with Equations (3.121)-<br />

(3.122) it is seen that at t 0 the phasor is equal to the SV (with the exception of scaling). For<br />

sinusoidal quantities in steady state the phasors and SVs trace a circle and any imbalance<br />

transient condition causes the phasor trajectory to deviate from the circle. In contrast,<br />

nonsinusoidal quantities have a SV trajectory that is not circular in the steady state and these<br />

cannot be represented by phasors.<br />

Returning to Equations (3.116)-(3.118) it is seen that the phasor transform takes a cosinusoidal<br />

quantity to a stationary vector in the complex plane; this is the phasor domain. It is common<br />

practice to say that the phasor rotates, but the phasor itself ( X ) does not rotate—rotation is<br />

141

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