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On Erd˝os-Gallai and Havel-Hakimi algorithms

On Erd˝os-Gallai and Havel-Hakimi algorithms

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<strong>On</strong> Erdős-<strong>Gallai</strong> <strong>and</strong> <strong>Havel</strong>-<strong>Hakimi</strong> <strong>algorithms</strong> 29<br />

as n → ∞. This is asymptotically equal to<br />

<br />

2n + 1<br />

n + 1<br />

=<br />

2n − 1<br />

n<br />

4n + 2<br />

n + 1<br />

2<br />

= 4 − = 4 + o(1). (53)<br />

n + 1<br />

It is interesting to observe that by (45) the average block length in a r<strong>and</strong>om<br />

n-regular sequence is<br />

r 1<br />

ej =<br />

r<br />

n<br />

≈ 2 (54)<br />

r(b)<br />

j=1<br />

approximately, as n → ∞. This fact could be interpreted as if blocks in the<br />

beginning of the sequence were significantly longer. However, fixing rn(b) = r<br />

we find that the lengths of the r blocks are exchangeable r<strong>and</strong>om variables with<br />

equal expectation n/r. At first sight this two facts seem to be in contradiction.<br />

The explanation is that exchangability only holds conditionally. Blocks in the<br />

beginning do exist even for smaller rainbow numbers, when the average block<br />

length is big, while blocks with large index can only appear when there are<br />

many short blocks in the sequence.<br />

The following assertion gives the number of zerofree sequences <strong>and</strong> the ratio<br />

of the numbers of zerofree <strong>and</strong> regular sequences.<br />

Corollary 18 The number of the zerofree n-regular sequences Rz(n) is<br />

<br />

2n − 2<br />

Rz(n) =<br />

n − 1<br />

<strong>and</strong><br />

Rz(n)<br />

lim<br />

n→∞ R(n)<br />

<br />

(55)<br />

1<br />

= . (56)<br />

2<br />

Proof. (55) identical with (24), (56) is a direct consequence of (24) <strong>and</strong> (25).<br />

<br />

As the experimental data in Figure 8 show, Ez(n)<br />

R(n)<br />

≈ 1<br />

4 .<br />

The following lemma allows that the algorithm Erdős-<strong>Gallai</strong>-Enumeraing<br />

tests only the zerofree even sequences instead of the even sequences.<br />

Lemma 19 If n ≥ 2, then the number of the n-graphical sequences G(n) is<br />

G(n) = G(n − 1) + Gz(n). (57)

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