Logical Decisions - Classweb
Logical Decisions - Classweb Logical Decisions - Classweb
for all measures i except 1 and 2. Thus all of these terms cancel out of the equation above leaving us with kU(a) 1 1 1 + kU(a) 2 2 2 = kU(b) 1 1 1 + kU(b). 2 2 2 since we are looking for the weights k 1 and k 2, we can rearrange this to give k in terms of k : so that 2 1 k 2(U 2(a 2) - U 2(b 2)) = k 1(U 1(b 1) - U 1(a 1)) k 2/k 1 = (U 1(b 1) - U 1(a 1))/(U 2(a 2) - U 2(b 2)). If we know the individual SUFs, we can compute all of the terms in the right hand side of the equation and thus we can find the ratio of the weights for measures 1 and 2. If we establish a tradeoff involving each of the measures and add the restriction that the weights must sum to 1 we can solve for the exact values of all the weights and thus completely define an additive MUF. Example of Relative Weight Computation Suppose we have two trucks, A and B that are identical except for their price and horsepower. A costs $10,000 and has 120 hp and B costs $12,000 and has 150 hp. Suppose also that we know that A and B are equally preferred and that the SUFs for cost and horsepower are known to give following SUF utilities: U cost($10,000) = 0.5 U ($12,000) = 0.4 cost U hp(120) = 0.2 U (160) = 1.0. hp This means that a change in the utility of cost of 0.5 - 0.4 = 0.1 is just compensated for by a change in the utility of horsepower of 1.0 - 0.2 = 0.8. Thus the ratio of the weights for cost and horsepower must be k hp/k cost = (U cost(b cost) - U cost(a cost))/(U hp(a hp) - U hp(b hp)) = (0.4 - 0.5)/(0.2 - 1.0) = (-0.1)/(-0.8) A-2 Appendix
= .125 Thus the weight for cost is eight times the weight for horsepower, given the ranges and preferences of the example. If these were the only measures in the example, their weights would have to sum to 1. This would mean that k cost = 0.8888... and k hp = 0.1111... since then we would have both k hp/k cost = 0.125 and k cost + k hp = 1.0. As a check we can confirm that U(A) = U(B): U(A) = kcostU cost(a cost) + khpU hp(a hp) = .8888U cost($10,000) + .1111U hp(120) = .8888x0.5 + .1111x0.2 = .4444 + .0222 = .4666 U(B) = kcostU cost(b cost) + khpU hp(b hp) = .8888U cost($12,000) + .1111U hp(160) = .8888x0.4 + .1111x1.0 = .3555 + .1111 = .4666 Thus these weights meet our requirement that equally preferred alternative receive equal overall utilities. Note that since the SUF utilities are used in computing the weights, changes in the range or SUF for either measure are automatically compensated for when the weights are computed. Appendix A-3
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for all measures i except 1 and 2. Thus all of these terms cancel<br />
out of the equation above leaving us with<br />
kU(a) 1 1 1 + kU(a) 2 2 2 = kU(b) 1 1 1 + kU(b).<br />
2 2 2<br />
since we are looking for the weights k 1 and k 2,<br />
we can rearrange<br />
this to give k in terms of k :<br />
so that<br />
2 1<br />
k 2(U 2(a 2) - U 2(b 2)) = k 1(U 1(b 1) - U 1(a 1))<br />
k 2/k 1 = (U 1(b 1) - U 1(a 1))/(U 2(a 2) - U 2(b 2)).<br />
If we know the individual SUFs, we can compute all of the terms<br />
in the right hand side of the equation and thus we can find the<br />
ratio of the weights for measures 1 and 2. If we establish a<br />
tradeoff involving each of the measures and add the restriction<br />
that the weights must sum to 1 we can solve for the exact values<br />
of all the weights and thus completely define an additive MUF.<br />
Example of Relative Weight Computation<br />
Suppose we have two trucks, A and B that are identical except for<br />
their price and horsepower. A costs $10,000 and has 120 hp and B<br />
costs $12,000 and has 150 hp. Suppose also that we know that A<br />
and B are equally preferred and that the SUFs for cost and<br />
horsepower are known to give following SUF utilities:<br />
U cost($10,000)<br />
= 0.5<br />
U ($12,000) = 0.4<br />
cost<br />
U hp(120)<br />
= 0.2<br />
U (160) = 1.0.<br />
hp<br />
This means that a change in the utility of cost of 0.5 - 0.4 = 0.1 is<br />
just compensated for by a change in the utility of horsepower of<br />
1.0 - 0.2 = 0.8. Thus the ratio of the weights for cost and<br />
horsepower must be<br />
k hp/k cost = (U cost(b cost) - U cost(a cost))/(U hp(a hp)<br />
-<br />
U hp(b hp))<br />
= (0.4 - 0.5)/(0.2 - 1.0)<br />
= (-0.1)/(-0.8)<br />
A-2 Appendix