Fullerenes 1
Fullerenes 1
Fullerenes 1
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Euler Theorem on Polyhedra 1<br />
v – e + f = χχ = 2(1 – g) (3)<br />
χχ = Euler’s Euler s characteristic<br />
v = number of vertices,<br />
e = number of edges,<br />
f = number of faces,<br />
g = genus ; (g = 0 for a sphere; 1 for a torus). torus<br />
A consequence:<br />
consequence<br />
A sphere can not be tessellated only by hexagons.<br />
<strong>Fullerenes</strong> need 12 pentagons (for closing the cage) and (N/2-10) (N/2 10) hexagons. hexagons<br />
In the opposite, a tube and a torus allow pure hexagonal nets.<br />
1. L. Euler, Elementa doctrinae solidorum, Novi Comment. Acad. Sci. I. Petropolitanae<br />
Comment. Acad. Sci. I. Petropolitanae<br />
1758, 4, 109-140.<br />
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