t - Bentham Science
t - Bentham Science
t - Bentham Science
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A.R. Memari Advanced Approach to Mitigate Magnetic Fields and Your Health 87<br />
10.2. Calculation of Loop Voltage<br />
The three phases of the transmission line are well capable to induce fluxes in this loop.<br />
The total flux, which is the vector sum of these three fluxes are responsible to generate<br />
the loop voltage.<br />
From Figure 47;<br />
'<br />
= 0<br />
"<br />
= 0.8442<br />
I = 460 Amps<br />
A<br />
Substituting the above values in Equation (20), the flux induced by phase A is given by;<br />
<br />
A<br />
= 3.7626 e-005<br />
Considering phase B;<br />
'<br />
= 0.<br />
5124<br />
"<br />
= 0.<br />
5124<br />
<br />
I B<br />
[ cos(<br />
120°<br />
) + * sin(<br />
° ) ]<br />
= 460 i 120<br />
Substitution of the obtained values in Equation (22) results in achieving<br />
<br />
B = 0<br />
Considering phase C;<br />
'<br />
= 0.<br />
8442<br />
"<br />
= 0<br />
<br />
I C<br />
[ cos(<br />
120°<br />
) + * sin(<br />
° ) ]<br />
= 460 i 120<br />
From Equation (24);<br />
<br />
C<br />
= 1.<br />
8813e<br />
005<br />
3.<br />
2585e<br />
005<br />
i<br />
Implementation of Equation (25) results in achieving the total flux induced in the<br />
auxiliary mitigating loop. Therefore;<br />
005<br />
005<br />
= 5.<br />
6439e<br />
3.<br />
2585e<br />
i<br />
<br />
T<br />
Finally, value of the loop voltage is determined by Equation (26).