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A.R. Memari Advanced Approach to Mitigate Magnetic Fields and Your Health 87<br />

10.2. Calculation of Loop Voltage<br />

The three phases of the transmission line are well capable to induce fluxes in this loop.<br />

The total flux, which is the vector sum of these three fluxes are responsible to generate<br />

the loop voltage.<br />

From Figure 47;<br />

'<br />

= 0<br />

"<br />

= 0.8442<br />

I = 460 Amps<br />

A<br />

Substituting the above values in Equation (20), the flux induced by phase A is given by;<br />

<br />

A<br />

= 3.7626 e-005<br />

Considering phase B;<br />

'<br />

= 0.<br />

5124<br />

"<br />

= 0.<br />

5124<br />

<br />

I B<br />

[ cos(<br />

120°<br />

) + * sin(<br />

° ) ]<br />

= 460 i 120<br />

Substitution of the obtained values in Equation (22) results in achieving<br />

<br />

B = 0<br />

Considering phase C;<br />

'<br />

= 0.<br />

8442<br />

"<br />

= 0<br />

<br />

I C<br />

[ cos(<br />

120°<br />

) + * sin(<br />

° ) ]<br />

= 460 i 120<br />

From Equation (24);<br />

<br />

C<br />

= 1.<br />

8813e<br />

005<br />

3.<br />

2585e<br />

005<br />

i<br />

Implementation of Equation (25) results in achieving the total flux induced in the<br />

auxiliary mitigating loop. Therefore;<br />

005<br />

005<br />

= 5.<br />

6439e<br />

3.<br />

2585e<br />

i<br />

<br />

T<br />

Finally, value of the loop voltage is determined by Equation (26).

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