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Hinton - The Fourth Dimension.pdf

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202<br />

THE FOURTH DIMENSION<br />

points LMN (fig. 128), and so in the region of our space<br />

Red axis<br />

before we go off into<br />

N<br />

the fourth dimension,<br />

we have the plane<br />

represented by LMN<br />

E F<br />

extended. This is what<br />

is common to the<br />

slanting space and our<br />

L C M space.<br />

White axis Yellow axis<br />

Fig. 128.<br />

This plane cuts the<br />

ochre cube in the triangle EFG.<br />

Comparing this with (fig. 72) oh, we see that the<br />

hexagon there drawn is part of the triangle EFG.<br />

Let us now imagine the tesseract and the slanting<br />

space both together to pass transverse to our space, a<br />

distance of one unit, we have in 1h a section of the<br />

tesseract, whose axes are parallels to the previous axes.<br />

<strong>The</strong> slanting space cuts them at a distance of five units<br />

along each. Drawing the plane through these points in<br />

1h it will be found to cut the cubical section of the<br />

tesseract in the hexagonal figure drawn. In 2h (fig. 72) the<br />

slanting space cuts the parallels to the axes at a distance<br />

of four along each, and the hexagonal figure is the section<br />

of this section of the tesseract by it. Finally when 3h<br />

comes in the slanting space cuts the axes at a distance<br />

of three along each, and the section is a triangle, of which<br />

the hexagon drawn is a truncated portion. After this<br />

the tesseract, which extends only three units in each of<br />

the four dimensions, has completely passed transverse<br />

of our space, and there is no more of it to be cut. Hence,<br />

putting the plane sections together in the right relations,<br />

we have the section determined by this particular slanting<br />

space: namely an octahedron.

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