2012-13 L3 MAF Topologie & analyse hilbertienne Feuille 1
2012-13 L3 MAF Topologie & analyse hilbertienne Feuille 1
2012-13 L3 MAF Topologie & analyse hilbertienne Feuille 1
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X <br />
(Ai)i∈I (Bj)j∈J X<br />
(∪i∈IAi) ∩ (∪j∈JBj) = ∪(i,j)∈I×J(Ai ∩ Bj) (∩i∈IAi) ∪ (∩j∈JBj) = ∩(i,j)∈I×J(Ai ∪ Bj)<br />
((Aj)j∈Ji )i∈I X<br />
∪i∈I(∪j∈Ji Aj) = ∪j∈∪i∈IJi Aj ∩i∈I(∩j∈Ji Aj) = ∩j∈∩i∈IJi Aj<br />
(Ai)i∈I (Bi)i∈I X<br />
( <br />
Ai) ∩ ( <br />
Bi) = <br />
(Ai ∩ Bi)<br />
i∈I<br />
i∈I<br />
i∈I<br />
X, Y f : X → Y <br />
A X f(A) = {f(x) x ∈ A} = {y ∈ B | ∃x ∈ A, y = f(x)}<br />
B Y f −1 (B) = {x ∈ A | f(x) ∈ B}<br />
∀A ∈ P(X), A ⊂ f −1 (f(A)) <br />
f injective ⇔ ∀A ∈ P(X), f −1 (f(A)) = A.<br />
<br />
∀B ∈ P(Y ), f(f −1 (B)) ⊂ B <br />
f surjective ⇔ ∀B ∈ P(Y ), f(f −1 (B)) = B.<br />
<br />
(Ai)i∈I X<br />
f(∪i∈IAi) = ∪i∈If(Ai) f(∩i∈IAi) ⊂ ∩i∈If(Ai) f <br />
<br />
(Bi)i∈I Y <br />
f −1 (∪i∈IBi) = ∪i∈If −1 (Bi) f −1 (∩i∈IBi) = ∩i∈If −1 (Bi)<br />
A ∈ P(X) B ∈ P(Y ) f −1 (B c ) (f −1 (B)) c f(A c ) (f(A)) c<br />
A, B A × B <br />
<br />
<br />
<br />
z <br />
z<br />
{0, 1} N Y X <br />
X Y Y N Y <br />
(E, d) δ(A) = sup x,y∈A d(x, y) <br />
A E δ(∅) = 0<br />
δ(A) = 0 A E δ( Ā) = δ(A)<br />
R Ai Ai (Ai) <br />
A1 = [−3, 1[∪]1, 2] ∪ {3, π} A2 = Z A3 = {(−1) p + 1/2p | p ∈ Z} A4 = Q A5 =] − ∞, 3/2] ∩ Q
R R G <br />
(R, +) G = aZ a <br />
G R R G<br />
G + = {g ∈ G , g > 0} m = inf G +<br />
m > 0 m ∈ G + G = mZ<br />
m = 0 m ∈ G + G R<br />
a, b b = 0 a<br />
b /∈ Q Ga,b := aZ + bZ <br />
R R<br />
a /∈ Q {cos(na) , n ∈ Z} [−1, +1]<br />
π<br />
Ga,2π<br />
R 2 R 2 <br />
<br />
A = (] − ∞, −1] × {0}) ∪ ([−1, 1[×[−1, 1[) ∩ (R ∗ × R) B = Q × (R \ Q)<br />
C = {(x, y) ∈ R 2 x 2 + y 2 ≤ 2, (x − 1) 2 + y 2 > 1} D = {(x, y) ∈ R 2 x 2 − sin y ≤ 4}<br />
E = {(x, y) ∈ [0, 1] 2 cos x > 0} k ∈ R ∗ + Fk = ∪n∈N ∗Hk,n Fk,n <br />
(1/n, 1/n) k/n<br />
A X <br />
A X<br />
(X, d) Y <br />
X f : Y → R k ∀x, y ∈ Y |f(x) − f(y)| ≤<br />
k d(x, y) x ∈ X y ∈ Y fy(x) = f(y) + k d(x, y)<br />
x ∈ X {fy(x)|y ∈ Y } f(z) − k d(z, x)<br />
z ∈ Y g(x) <br />
x ∈ Y g(x) = fx(x)<br />
g : X → R k<br />
f X <br />
Y X <br />
E (Ai)i∈I <br />
E ∪i∈I Ai (∪i∈IAi) E = R 2 I = N ∗ Ai = {(1/i, 1/j) | j ∈<br />
N ∗ } <br />
(∩i∈IAi) ⊂ ∩i∈I Ai <br />
A <br />
A (A) A<br />
A <br />
A A ∩ (A) = ∅<br />
A (A) ⊂ A<br />
A (A) = ∅<br />
A ⊂ (A) ( A) ⊂ (A) R <br />
<br />
A B <br />
(A ∪ B) ⊂ (A) ∪ (B)<br />
R <br />
Ā ∩ ¯ B = ∅ ⇒ (A ∪ B) = (A) ∪ (B)