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M P BHOJ (OPEN) UNIVERSITY, BHOPAL<br />

ASSIGNMENT QUESTION PAPER<br />

2009-10<br />

CLASS : M.Sc. Final SUBJECT: Mathematics<br />

Paper - III - Operation Research<br />

funsZ'k %&<br />

1- lHkh iz'u Lo;a dh gLrfyfi esa gy djuk vfuok;Z gSA 2- nksuksa l=h; iz'ui= gy djuk vfuok;Z gsa<br />

3- l=h; dk;Z mÙkjiqfLrdk ds vafre i`"B ij lacaf/kr fo"k; dh laiUu<br />

laidZ d{kkvksa dh frfFk;ksa ,oa ijke'kZnkrk ds uke ,oa in dk<br />

vo'; mYys[k djsaA<br />

5- l=h; dk;Z mÙkjiqfLrdk,a tek djus dh vafre frfFk 20<br />

vizsy 2010 gSA<br />

4- vafre frfFk mijkar l=h; dk;Z mÙkjiqfLrdkvksa dks ekU; ugha djrs<br />

gq, ewY;kafdr ugha dh tkosxhA<br />

6- l=h; dk;Z mÙkjiqfLrdk,a tek djus dh jlhn vo'; izkIr dj ysaA<br />

7- nks l=h; dk;Z izkIrkadksa esa ls fdlh ,d esa vf/kdre vad dh iwoZ izpfyr O;oLFkk ds LFkku ij nksuksa l=h; dk;ksZa ds izkIrkadksa<br />

ds vkSlr vad l=kar ijh{kk ifj.kke esa tksM+s tk,axsA lHkh iz'uksa ds vad leku gSaA<br />

First Assignment Max Marks - 30<br />

Q.1. A Company produces two kinds of leather belts A and B . A is of superior quality and B is of<br />

lower quality. The respective profits are Rs. 10 and Rs. 5 per belt. The supply of raw material is<br />

sufficient for making 850 belts per day. For belt A special type of buckle is required and 500 are<br />

available per day. There are 700 buckles available for belt B per day. Belt A needs twice as much<br />

time as that required for belt b. & company can produce 500 belts of all of them were of type A.<br />

Formulate LPP & solve it graphically.<br />

Q2. Solve following transportation problem & test the optimality by MODI method.<br />

F1 F2 F3 F4 SUPPLY<br />

W1 21 16 25 13 8<br />

W2 17 18 14 23 10<br />

W3 32 27 18 41 12<br />

DEMAND 20 15 15 30 20<br />

Q3. Use Branch & Bound technique to find an solution<br />

Max. Z = x 1 + 4 x2<br />

Sub. to 2x1 + 4x2 ≤ 7<br />

5x1 + 3x2 ≤ 15, x1 , x2 ≥ 0.<br />

Q4. Solve the following pay-off matrix , determine the optimal strategies and value of game<br />

A = 5 1<br />

3 4<br />

Q5. Solve the following by Simplex method to<br />

Minimize z = x1 – 3x2 + 2x3<br />

Sub. to 3x1 – x2 + 3x3 ≤ 7<br />

-2x1 + 4x2 ≤ 12 & x1, x2 ≥ 0<br />

Second Assignment Max Marks – 30<br />

P.T.O.

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