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KURENAI : Kyoto University Research Information Repository

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v v<br />

Here, S is a thickness of velocity boundary layer and related to wall shear<br />

v stress by<br />

Tw1.571y=022(46)<br />

v Substituting Egs.(10) and (45) into Eq.(11) and integrating,<br />

for Pr > 1<br />

for Pr < 1<br />

u mS6<br />

6a at(6vgw)+16~ ax[gw6t{St15(St}3}] C(47)<br />

vvPp ,<br />

uSS<br />

6X at(St~gw}+16X 3x~gw6t6v{8 5(St}+24(St}2}]<br />

vv<br />

+ 6X ax{qw6t( 1 -S!)3} =P(48)<br />

u<br />

•<br />

t P<br />

As shown in Eq.(47) the contribution of (S t/6v) is considerably larger than<br />

that of 15 (6t/6 v)3 in the second term of the left hand side of Eq.(47),<br />

even if (St/6 v) is close to unity. As already shown in previous sections<br />

transient heat transfer coefficients are largerthan those of steady state .<br />

This means the thickness of thermal boundary layer, S t, is thinner in tran-<br />

sient case than in steady state case. Since velocity boundary layer<br />

is assumed to be steady state one in this analysis,(S<br />

, Sy,<br />

t/Sv) is smaller in<br />

transient case than in steady state case. Therefore, in transient case ,<br />

the contribution of (dt/Sv)is much greater than that of15(6t/v<br />

second term of the left hand side of Eq.(47). In view of this<br />

6)3 in the<br />

, if one<br />

approximates {6t/6v 5(6t/6v)3} by (St/6 v) in Eq.(47), Eq.(47) becomes<br />

the same equation as Eq.(29) which is for Pr >> 1. Therefore<br />

124<br />

, it may

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