\fdO'^ - Old Forge Coal Mines

76 ARITHMETIC.
correction. This, multiplied by the second figure of the root,
8, gives 1,568. Adding this product to the last complete
divisor, and annexing two ciphers, gives 1,387,200 for the
next trial divisor. Adding the second figure of the root, 8,
to the first new correction, 196, we obtain 204 for the new
second correction. Dividing the dividend by the trial divisor
1,387,200, we see that it is contained about 9 times. Write
9 as the third figure of the root. Annex one cipher to the
new second correction, and to this add the third figure of the
root, 9, thereby obtaining 2,049. This, multiplied by 9, the
third figure of the root, equals 18,441, which, added to the
trial divisor, 1,387,200, forms the complete divisor 1,405,641.
Multiplying the complete divisor by the third figure of the
root, 9, and subtracting, we have a remainder of 597,231.
We then find the fourth figure by division, as shown.
{V) 4 16 f 7 4'0 8 8 = 42 Ans.
4 32 64
120
5
125
8 4800 10088
4 244 10088
120 6044
2
122
(^) 4 16 f 9 2'416 = 45.212— Ans.
4 32 64
^ 4800 28416
i_ 6 25 2 712 5
5425 1291000
650 1220408
5 607500 612912)70592.000(.115
130 2704 612912
i_ 610204 930080
^^^^ 2708 612912
2
J352 612912 3171680
3064560
2
1361 107120