\fdO'^ - Old Forge Coal Mines
\fdO'^ - Old Forge Coal Mines
\fdO'^ - Old Forge Coal Mines
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ARITHMETIC. 76<br />
Explanation.— (1) When extracting the cube root we<br />
divide the power into periods of three figures each. Always<br />
begin at the decimal point, and proceed to the left in point-<br />
ing off the whole number, and to the right in pointing off<br />
the decimal. In this power >^. 32768, a cipher must be<br />
annexed to 68 to complete the second decimal period.<br />
Cipher periods may now be annexed until the root has as<br />
many figures as desired.<br />
(2) We find by trial that the largest number whose cube<br />
is contained in the first period, 327, is 6. Write 6 as the first<br />
figure of the root, also at the extreme left at the head of<br />
column (1). Multiply the 6 in column (1) by the first figure<br />
of the root, 6, and write the product 36 at the head of<br />
column (2). Multiply the number in column (2) by the<br />
first figure of the root, 6, and write the product 216 under<br />
the figures in the first period. Subtract and bring down<br />
the next period 680; annex it to the remainder 111, thereby<br />
obtaining 111,680 for a new dividend. Add the first figure<br />
of the root, 6, to the number in column (1), obtaining<br />
12, which we call the first correction ; multiply the first<br />
correction 12 by the first figure of the root, and we obtain<br />
72 as the product, which, added to 36 of column (2), gives<br />
108. Annexing two ciphers to 108, we have 10,800 for the<br />
trial divisor. Dividing the dividend by the trial divisor, we<br />
see that it is contained about 8 times,<br />
so we write 8 as the<br />
second figure of the root. Add the first figure of the root<br />
to the first correction, and we obtain 18 as the second cor-<br />
rection. To this annex one cipher, and add the second figure<br />
of the root, and we obtain 188. This, multiplied by the second<br />
figure of the root, 8, equals 1,504, which, added to the<br />
trial divisor •<br />
10,800, forms the complete divisor 12,304.<br />
Multiplying the complete divisor 12,304 by 8, the second<br />
figure of the root, the result is 98,432. Write 98,432 under<br />
the dividend 111,680; subtract, and there is a remainder<br />
of 13,248. To this remainder annex the next period 000,<br />
thereby obtaining 13,248,000 for the next new dividend.<br />
(3) Adding the second figure of the root, 8, to the number<br />
in column (1), 188, we have 196 for the first new