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\fdO'^ - Old Forge Coal Mines

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72 ARITHMETIC.<br />

in the root. Write in the root, as shown, and also add it<br />

to the trial divisor, 600, and annex a cipher, thereby making<br />

the next trial divisor 6,000. Bring down the next period, 99.<br />

The trial divisor 6,000 is contained in 000099, times, so we<br />

place as the next figure in the root, as shown, and also add<br />

it to the trial divisor 6,000, and annex a cipher, thereby mak-<br />

ing the next trial divisor 60,000. Bring down the next period,<br />

40, and annex it to the dividend already obtained to form<br />

the new dividend, 00009940, and divide it by the trial divisor<br />

60,000. 60,000 is contained in 00009940, times, so we place<br />

another cipher in the root, as shown, and also add it to the<br />

trial divisor 60,000, and annex one cipher, thereby making<br />

the next trial divisor 600,000. Bring down the next period,<br />

09, and annex it to the dividend already obtained to form<br />

the new dividend, 0000994009, and divide it by the trial divisor<br />

600,000. 600,000 is contained in 0000994009 once,<br />

we place 1 as the next figure in the root, and also add it<br />

so<br />

to<br />

the trial divisor 600,000, thereby making the complete divisor<br />

600,001. Multiply the complete divisor, 600,001, by 1, the<br />

sixth figure in the root, and subtract the result obtained<br />

from the dividend. The remainder is 394,008, to which we<br />

annex the next period, 00, to form the next new dividend, or<br />

39,400,800. Add the sixth figure of the root, or 1, to the<br />

divisor 600,001, and annex a cipher, thus obtaining 6,000,020<br />

as the next trial divisor. Dividing 39,400,800 by 6,000,020,<br />

we find 6 to be the next figure of the root. Adding this last<br />

figure, 6, to the trial divisor, we obtain 6,000,026 for our<br />

next complete divisor, which, multiplied by the last figure of<br />

the root, or 6, gives 36,000,156, which write under 39,400,800<br />

and subtract. Since there is a remainder, it is clearly evident<br />

that the given power ^is not a perfect square, so we<br />

place -\- after the root. Since the next figure is 5, the<br />

answer is — .<br />

3,000.017<br />

In this problem there are seven periods—four in the whole<br />

number and three in the decimal—<br />

hence, there will be seven<br />

figures in the root, /our figures constituting the whole<br />

number, and three figures the decimal of the root.<br />

4/9,000,099.4009 = 3,000.017 -.<br />

Hence,

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