\fdO'^ - Old Forge Coal Mines

68 ARITHMETIC.
(128) {a) .0133' =.0133 X.0133 X .0133 =.000002352637.
Ans.
Since there are 4 decimal places in the multiplicand and 4
in the multiplier, we must point off 4 + 4=8 decimal
places in the product; but, as
• 0133 there are only 5 figures in the
.0133
product, we prefix three ciphers
3 9 9 to form the eight necessary deci-
3 9 9 mal places in the first product.
13 3
———————
.00017689
Since there are 8 decimal places
in the multiplicand ^ and 4 in the
,.
•
,^.
^
^ «: o ,
multiplier, we must point off 8 -h
—! 4 = 12 decimal places in the prod-
5 3 6 7 uct ; but, as there are only 7
5 3 6 7
figures in the product, we prefix
17 6 8 9 5 ciphers to make the 12 neces-
.000002352637 sary decimal places in the final
{b)
product.
301.011* = 301.011 X 301.011 X 301.011 =
301.011
301.011
27,273,890.942264331. Ans.
Since there are 3 decimal
places in the multiplicand
3 01011 and 3 in the multiplier, we
3 01011 must point off 3 + 3 = 6
3 010110 decimal places in the first
9030330 product.
90607.622121
3 01.011 Since there are 6 decimal
90607622121 places in the multiplicand
90607 622121 and 3 in the multiplier, we
906076221210 must point off 6 + 3 = 9
718228663630 decimal places in the final
27273890.942264331
product.