\fdO'^ - Old Forge Coal Mines

ARITHMETIC. 67
(c) l' = lxlXlXlXlXlXl = l. Ans.
{d) .01* = .01 X .01 X .01 X .01 = .00000001. Ans.
Since there are 2 decimal places in the multiplicand and
in the multiplier, we must point off 2+2 = 4 decimal
places in the first product; but, as there
.01 is only 1 figure in the product, we
.01 prefix 3 ciphers to make the 4 necessary
decimal places.
Since there are 4 decimal places in
the second multiplicand and 2 in the
.000 001 multiplier, we must point off 4-|-2=6
•01 decimal places in the second product.
.0 0000001 It is necessary to prefix 5 ciphers to
make G decimal places.
Since there are 6 decimal places in the third multiplicand
and 2 in the multiplier, we must point off G + 2 = 8 decimal
places in the product. It is necessary to prefix 7 ciphers to
make 8 decimal places in the final product.
(c) .1" = .1 X .1 X .1 X .1 X .1 = .00001. Ans.
Since there is 1 decimal place in the multiplicand and
I in the multiplier, we must point off 1 + 1 = 2 decimal
places in the first product. It is necessary to
.1
prefix 1 cipher to the product.
•1 Since there are 2 decimal places in the
01 second multiplicand and 1 in the multiplier,
I we must point off 2+1 = 3 decimal places
in the second product. It is necessary to
prefix 2 ciphers to the second product.
Since there are 3 decimal places in the
.00 01 third multiplicand and 1 in the multiplier, we
• 1 must point off 3+1 = 4 decimal places in
.0 001 the third product. It is necessary to prefix
3 ciphers to this product.
Since there are 4 decimal places in the fourth multi-
plicand and 1 in the multiplier, we must point off 4 + 1
or 5 decimal places in the final product. It is necessary to
prefix 4 ciphers to this product.