\fdO'^ - Old Forge Coal Mines

54 ARITHMETIC.
(108) In multiplication of denominate numbers, we
place the multiplier
multiplicand,
under the lowest denomination of the
as
17 ft. 3 in.
51
879 ft. 9 in.
and begin at the right to multiply. 51 X 3 = 153 in. As
there are 12 inches in 1 foot, in 153 in. there are as many
feet as 12 is contained times in 153, or 12 feet and 9 inches
remaining.
Place the 9 inches under the inches, and reserve
the 12 feet. 51 X 17 ft. = 867 ft. 867 ft. + 12 ft. (reserved)
= 879 ft.
879 feet can be reduced to higher denominations by divi-
ding by 3 feet to find the number of yards, and by 5 — yards
to find the number of rods.
3 )879 ft. 9 in.
5.5 )293 yd.
5 3 rd. 1^ yd.
Then, answer = 53 rd. 1^ yd. ft. 9 in. ; or 53 rd. 1 yd. 2
ft. 3 in.
(109) qt- Pt. gi-
3 134.7
18.2qt.
or, 1 8 qt. Opt. 1.7 gi.
or, 4 gal. 2 qt. Opt. 1.7 gi. Ans.
Place the multiplier under the lowest denomination of the
multiplicand, and proceed to multiply. 4.7 X 3 gi. = 14.1 gi.
as 4 is
As 4 gi. = 1 pt. , there are as many pints in 14. 1 gi.
contained times in 14.1 = 3.5 pt. and .1 gi. over. Place .1
under gills and carry the 3.5 pt. forward. 4.7 X 1 pt. = 4.7
pt. ; 4.7 + 3.5 pt. = 8.2 pt. As 2 pt. = 1 qt., there are as
many quarts in 8.2 pt. as 2 is contained times in 8.2 = 4.1
qt. and no pints over. Place a cipher under the pints, and
carry the 4.1 qt. to the next product. 4.7 X 3 qt. = 14.1;
14.1 + 4.1 = 18.2 qt. The answer now is 18.2 qt. pt. .1
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