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\fdO'^ - Old Forge Coal Mines

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304 TRACK WORK.<br />

(1008) 8 ft. G in. = 102 in. 15 ft. 3 in. = 183 in. 183<br />

in. — 102 in. = 81 in. 81 in. h- 48 = 1.69 in. = 1|| in. Ans.<br />

(1009)<br />

See Art. 1698.<br />

(1010) We find the crotch frog distance as follows:<br />

From the table of Tangent and Chord Deflections, we find<br />

the tangent<br />

deflection of a 100-ft. chord of a 10° curve is<br />

8.72 ft. One-half the gauge is 2.35 ft. Calling<br />

frog distance x^ we have the proportion<br />

8.72 : 2.35:: 100' : .jr*;<br />

the crotch<br />

, 100-^ , X 2.35 - .__ ,<br />

-i- whence, = — = 2,695, nearly,<br />

8. < 2<br />

and X = 51.9 ft. Ans.<br />

The central angle for a chord of 51.9 ft. is 6' X 51.9 =<br />

311.4' = 5° 11.4', and the angle of the crotch frog is 5° 11.4' x<br />

2 = 10° 22.8'. Ans.<br />

(lOll)

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