\fdO'^ - Old Forge Coal Mines

18
ARITHMETIC.
3 3
(e) 15-r-7-43-= ? Before proceeding with the division,
4 8
reduce both of the mixed numbers to improper fractions.
Thus i53_(15x4H-_3_60 + 3_63 ^^^ ^3 _ (4 X 8) + 3 _
32 + 3 35
—-!— = — -.
_„ ,
.
, The problem
63 35 ,
. , ,
is now 8 8
—- -^ -— = ?
4 8
As before,
^
. ,. . ,
,
.
, 63. 35 63^ 8 63x8
„- =
mvert the divisor and multiply —-7-— = .
; ---X-^= 4; 8 4 oo 4 X oo
504 _ 252 _ 126 _ 18
140 ~ 70 ~ 35 " 5 *
5)18(3^ Ans.
1^ ^
3
When the denonmiators of the fractions to be added are
alike, we know that the units are divided into the same
number ofparts (in this case eighths) ; we, therefore, add the
numerators of the fractions to find the number of parts
g
(eighths) taken or considered, thereby obtaining — or 1 as
8
the sum.
(39) When the denominators are not alike we know that
the units are divided into unequal parts, so before adding
them we must find a common denominator for the denom-
inators of all the fractions. Reduce the fractions to fractions
having this common denominator, add the numerators and
write the sum over the common denominator.
In this case, the least common denominator, or the least
number that will contain all the denominators, is 16; hence,
we must reduce all these fractions to sixteenths and then add
their numerators.
13 5
7- + H- + = T7: ?
4 o lb
To reduce the
1
fraction — to
4
a fraction
having 16 for a denominator, Ave must multiply both terms