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\fdO'^ - Old Forge Coal Mines

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RAILROAD CONSTRUCTION. 283<br />

Art. 1462. The height of top of the covering flags is<br />

5 feet. 1^ times 5 feet =7.5 feet. Adding 2 feet, we have<br />

length of the wing walls, i. e. , the distance from inside face<br />

of the side walls to the end of the wing walls, 7.5 + 2 = 9<br />

feet G inches. Ans.<br />

(824) The span of a box culvert should not exceed<br />

3 feet. When a larger opening is required, a double box cul-<br />

vert with a division wall 2 feet in thickness is substituted,<br />

(825)<br />

(826)<br />

(827)<br />

(828)<br />

See Art. 1 462.<br />

See- Art. 1462.<br />

See Art. 1463.<br />

See Art. 1465.<br />

(829) The thickness of the base should be -j^ of the<br />

height. The height is 16 feet and the thickness of the base<br />

should be t*^ of 16 feet, or 6.4 feet. Ans.<br />

(830)<br />

(831)<br />

See Art. 1468.<br />

See Art. 1468.<br />

(832) Trautwine's formula for finding the depth of<br />

keystone (see formula 103, Art. 1469), is as follows:<br />

J .1 ri . • r 4/radius of arch +A^ span ,<br />

depth of keystone m feet=^^<br />

j<br />

!-^—^-<br />

, , ,<br />

\-0.2 foot.<br />

In this example the arch being semicircular, the radius and<br />

half-span are the same. Substituting known values in the<br />

given formula, we have<br />

4/T5 + 15<br />

depth of keystone =<br />

j 1-<br />

0.2 foot =1.57 feet. Ans.<br />

Applying Rankine's formula (formula 104), depth of<br />

keystone = -/. 12 radius, we have depth of keystone =<br />

y. 12 X 15= 1.34 feet. Ans.

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