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\fdO'^ - Old Forge Coal Mines

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278 RAILROAD LOCATION.<br />

curve (which we will call Sta. 0) is 110 ft., the elevations ot<br />

the grades for all the stations of the curve are the following:<br />

Stations. Elevation of Grade.<br />

110.00<br />

1 110.85<br />

2 111.40<br />

3 111.65<br />

4 111.60<br />

5 111.25<br />

110.60<br />

(807) In Fig. 72, A 6^ is an ascending grade of 1 per<br />

cent., and C B is sl descending grade of 0.8 per cent,, which<br />

,,-'- — « 6 « d • f~ g<br />

Fig. 78.<br />

are the grades specified in Question 806. To draw these<br />

grade lines, first draw a horizontal line A D ^ in. long,<br />

which will include both grade lines to a scale of 100 ft. to<br />

the inch. Divide this line into six equal parts, with the<br />

letters «, b, c, etc., at the points of division. Now, ^ being<br />

300 ft. from A, the height of the original grade line above ^<br />

is the rate of grade. ^= 1.0 ft. X 3 = 3 ft., which distance<br />

we scale off above d to a. vertical scale of 5 ft. to the inch,<br />

locating the point C. The grade of C B is — 0.8 ft. per<br />

100 ft. Consequently, B, which is 300 ft. from C, is 0.8 ft.<br />

X 3 = 2.4 ft. below C, and the height of B above A D is<br />

equal to 3.0 ft. — 2.4 ft. = 0.6 ft. We scale off above D the<br />

distance 0.6 ft., locating B. Joining A C and B C, we have<br />

the original grade lines, which are to be united by a vertical<br />

curve. Now, the elevation of the grade at Sta. is 110 ft,<br />

The line A D has the same elevation. We have already<br />

determined the heights of the curve above this line at the<br />

several stations on the curve. Accordingly, we lay off<br />

these distances, viz., at ^, corresponding to Sta. 1, 0.85 ft. ;<br />

at r, Sta. 2, 1.4 ft. ; at d^ Sta. 3, 1.65 ft., etc., marking each

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