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\fdO'^ - Old Forge Coal Mines

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228 STRENGTH OF MATERIALS.<br />

(604) Using formula 87,<br />

*<br />

12,000<br />

^<br />

12,000<br />

(605) The radius r of the gear-wheel is 24' Using<br />

formula 80, ^=c {TPr = . 297 f350 x 24 = 2. 84'. Ans.<br />

(606) Area of cylinder = .7854 x 12' =113.1 sq. in.<br />

Total pressure on the head = 113.1 X 90 = 10,179 lb.<br />

Pressures on each bolt = — ^^ = 1,017.9 lb.<br />

Using formula 65,<br />

F= A S, or A=^=<br />

/* 1 017 9<br />

'<br />

:!^ = .5089 sq. in., area of bolt.<br />

.5089<br />

'<br />

Diameter of bolt = |/ = .8", nearly. Ans.<br />

(607) (a) The graphic solution is clearly shown in Fig.<br />

53. On the vertical through JF., the equal loads F^ and F^<br />

1 Ton. . 1 Ton,<br />

CB IS'— ^<br />

Scale of forces 1=2000 lb.<br />

Scale of distance 1^6^<br />

Fio. 53.<br />

are laid off to scale, 0-1 representing F^ and 1-2 representing

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