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\fdO'^ - Old Forge Coal Mines

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218 STRENGTH OF MATERIALS.<br />

n o. I// 38,000 X 56.945<br />

Hence, 2AIV=<br />

^ ^ ^^^^<br />

'^<br />

.<br />

38,000 X 56.945 _<br />

24X6X3.25 -*'^^*^^- ^^s.<br />

(581) {^) From the table of Bending Moments,<br />

From formula 74,<br />

«;Xl92' _5y<br />

^'^- '<br />

8 -A'<br />

5, = 7,200;/=8; 7=1^^^ = ^; ^ = 1-^=5.<br />

Then<br />

jf; =<br />

^^ X 192' ^ 7,200 ^^ 2,000<br />

7,200 X 2,000 X 8<br />

8 X 12 X 5 X 192 X 192<br />

12 X 5<br />

6.51 lb. per in. = 6.51 X 12 = 78.12 lb. per ft. Ans.<br />

/A\ r<br />

1 A ^3 10 X 2" 80 ,^<br />

w X 192' _ 7,200<br />

80<br />

8 8 12 X 1<br />

7,200 X 80 X 8 . ^ ,,<br />

w = -—^— -— —- = 1.3 lb. per m.<br />

8 X 12 X 192 X 192<br />

= 1.3 X 12 = 15.6 lb. per ft. Ans.<br />

(582) {(t) From the table of Bending Moments, the<br />

K T///S<br />

deflection of a beam uniformly loaded is —— ^ , . In<br />

384 Ji I<br />

Example 579, W= 874 X 20 = 17,480 lb.; /= 240', E =<br />

25,000,000, and 7=280.<br />

XX A a ^' 5X 17,480 X 240' . . ,^<br />

Hence, deflection s = 77-7^—<br />

^- = \,.r. r.,^r.—^t7T7: -45 m. Ans.<br />

'<br />

^<br />

384 X 20,000,000 X 280<br />

1 IfV<br />

{b) From the table of Bending Moments, s = — ^ , .

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