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\fdO'^ - Old Forge Coal Mines

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198 HYDROMECHANICS.<br />

Pressure per square inch exerted by piston = lb.<br />

.19635<br />

Hence, according to Pascal's law, the pressure on the<br />

plunger is ^^ x 78.54 = 40,000 lb. Ans.<br />

(d) Velocity ratio = li : .00375 = 400 : 1. Ans.<br />

{c) According to the principle given in Art. 981, Px<br />

1 — inches = Wx distance moved by plunger, or 100 X<br />

1 5- = 40,000 X required distance; hence, the required dis-<br />

tance = ^^^ ^}}^ = .00375 in. Ans.<br />

40, 000<br />

(495) {a) Use formula 44, and multiply by 7.48 and<br />

60 to reduce the discharge from cu. ft. per sec. to gal. per<br />

min.<br />

^„ = .41 ^/^[/J* - 4/^'] X 60 X 7.48 =<br />

.41 X 12 X 4/64:32 rWo + ^V- 4/9^1 X 60 X 7.48 =<br />

(d)<br />

In the second case,<br />

(2a = .41 X^ X 4^64:32 rW9 + i|y- 4/9^1x60x7. 48 =<br />

13,323 gal.<br />

Ans.<br />

(496) {a) Area of weir = 14 X 20 ^ 144 sq. ft. Use<br />

formula 32, and divide by^O X L^8 to reduce gal. per min.<br />

to cu. ft. per sec.<br />

Q 13,502X144 ,-.«., A<br />

'^m = -^ = TTx s-77; Ti = 777: I0.47 ft. per sec. Ans.<br />

A 60 X 7.48 X 14 X 20 ^<br />

... 13,323X144 ..^„„r. A<br />

(^> ^"= =<br />

60X7.48X14X20 ^^-^^^^P^^^"- ^^•<br />

(497) (a) See Art. 997. .<br />

J^=2 lb. 8|oz. =40.5oz.<br />

w = 12 oz.<br />

W = 1 lb. 11 oz. = 27 oz.

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