\fdO'^ - Old Forge Coal Mines

Again,
ARITHMETIC. 9
6x8x4xl _
8X3X1X1
6 in the dividend and 3 in the divisor are divisible
by 3, since 6 divided by 3 equals 2, and 3 divided by 3 equals
1. Cross off the 6 and write the 2 over it ; also, cross off the
3 and write the 1 under it. Thus,
2
0x8x4x1 ^
8x^x1x1
1
The 6 and 3 are not to be considered any longer, and, in
fact, may be erased entirely and the 2 and 1 placed in their
stead, and treated as if the 6 and 3 never existed.
2X8X4X1 _
8X1X1X1
Thus,
Canceling the 8 in the dividend and the 8 in the divisor,
the result is
1
2x^4x1 ^ 2x1x4x1
^xlxlxl~lxixlxl*
1
Since there are no two remaining numbers (one in the
dividend and one in the divisor) divisible by any number trs.-
cept 1, without a remainder, it is impossible to cancel further.
Multiply
all the uncanceled numbers in the dividend
together, and divide their product by the product of all
the uncanceled numbers in the divisor. The result will be the
quotient. The product of all the uncanceled numbers in
the dividend equals 2x1x4x1 = 8; the product of all the
uncanceled numbers in the divisor equals 1x1X1X1 = 1.
„ 2X1X4X18 _.
Hence, :; ; :; =
- = 8. Ans.
IXlXlXl 1
2
Or, 4>