\fdO'^ - Old Forge Coal Mines

HYDROMECHANICS. 195
^-J '^gh _J ^X 32.10 X45~_
z/-r ^^-r ^^^^^^^^^^^g^_5d.9tt. persec. Ans.
'
A-"
^
(6^ X. 7854)*
{b) 2.304X10=33.04 ft. = height of column of water
which will give a pressure of 10 lb. per sq. in. 45 + 23.04
= 68.04 ft.
_ V2 X 32.16 X 68.04 - =66.28 ft. per sec. Ans.
(1.5* X .7854)
^
(6* X .7854)'
(485)
Use formula 48.
Q = .0408 «^V„. = .0408 x 6' X 7.5 = 11.016 gal. per
sec. Ans.
(486) 14' X .7854 X 27 = volume of cylinder = volume
of water displaced.
14' X .7854 X 27 X .03617 = 150 lb., nearly, = weight of
water displaced.
(14' - 13') X .7854 X 27 = volume of the cylinder walls.
13' X .7854 X J X 2 = volume of the cylinder ends.
.261 lb. = weight of a cubic inch of cast iron, then,
[(14' - 13') X .7854 X 27 + 13' X .7854 X ^ X 2] X .261 =
167 lb., nearly, = weight of cylinder. Since weight of
cylinder is greater than the weight of the water displaced,
it will sink. Ans.
(487) 2 lb. — 1 lb. 5 oz. = 11 oz., weight of water.
1 lb. 15.34 oz. — 1 lb. 5 oz. = 10.34 oz., weight of oil.
10.34 ^ 11 = .94 = Sp. Gr. of oil. Ans.
(488) Head = 41 h- . 434 = 94. 47 ft. Using formula 36,
«;=.98i/2^/! =.98i/2 X 32.16 X 94.47 = 76.39 ft. per sec. Ans.
This is not the mean velocity, v„.
(489) (a)
Use formula 39.
(2a = .815^|/27^, or
1.5' X .7854
(2a = .815 X ,,'. X |/2X 32.16X94.47 X 60 =
144
46.77 cu. ft. per min. Ans.