\fdO'^ - Old Forge Coal Mines

(467)
HYDROMECHANICS. 191
Use formulas 46 and 45.
t' =2.315 /- 120 X 4 = 7.1728 ft. per sec.
.025 X 2,000
From the table in Art. 1033,/ = .0214 for v,^ = 6, and
.0205 for «;„. = 8. 8 - 6 = 2.
.0214 - .0205 = .0009. 7.1728 - 6 = 1.1728.
2 : 1.1728::. 0009 : ;r, or ;ir= .0005.
.0214- .0005 = .0209 =/for v^ = 7.1728.
Hence, the velocity of discharge =
«/„, = 2.315 lA
120 X 4
.0209 X 2,000 + i X 4
(468) {a) See Fig. 43. Area of
cylinder = 19' X .7854; pressure, 90
pounds per sq. in. Hence, the total
pressure on the piston is 19' X .7854
X 90 = 25,517.6 lb. =the load that
can be lifted. Ans.
{b) The diameter of the pipe has
no effect on the load which can be
lifted, except that a larger pipe will
lift the load faster, since more water
will flow in during a given time.
(469) {a) f=. 0205 for v^ = 8.
Therefore, using formula 47,
/i = - .0205 X 5,280 X 8'
5.3G X 10
8' = 130.73 ft. Ans.
+ .0233 X
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