\fdO'^ - Old Forge Coal Mines

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176 ELEMENTARY MECHANICS (412) Use formula 1 2. _ V4,000' X 2 . d^ : R':: W: zu, or d A 13,064 — 4,000 = 9,064 miles. Ans. = 13,064 mi., nearly. (41 3) Use formula 18. / = /^ = /1P# = ' ^32.16 1.7634 sec, nearly. (414) ^ = :5- 60 6 1.7634 X 140 = 246.876 ft. Ans. sec. Use formula 17. h^^gf = ^-X 32.16 X (ly = 1.78| ft. = 1 ft. 9.44 in. (416) See Arts. 906, 907. (41 6) See Arts.. 908, 909. Ans.
ELEMENTARY MECHANICS. 177 (417) No. It can only be counteracted by another equal couple which tends to revolve the body in an opposite direction. (418) See Art. 914. (419) Draw the quadrilateral as shown in Fig. 29. Divide it into two triangles by the diagonal B D. 'The center of gravity of the triangle B C D \s found to be at a, and the center of gravity of the triangle A B D is found to be at d (Art. 914). Join a and d by the line a d, which, on being measured, is found to have a length of 4. 27 inches. From C and A drop the perpendiculars C /'' and A G on the diagonal B D. Then, area of the triangle ABD= - (AGx lit B D), and area of the triangle B C D=\ {C F x B D). Measuring these distances, B Z> = 11', C F=5.l\ and A G= 7.7'. Area ABD=\ x7.7xll = 42.35 sq. in. Area BCD=\ X 5.1x11 = 28.05 sq. in. According to formula 20, the distance of O, the center of 28.05 X 4.27 gravity, from ^ is = 1. 7. Therefore, the cen- ^g^^^^^^ 3^ ter of gravity is on the line ^ ^ at a distance of 1.7' from b. (420) See Fig. 30. The center of gravity lies at the geometrical center of the pentagon, which may be found as follows : From any vertex draw a line to the middle point of the opposite side. Repeat the operation for any other vertex, and the intersection of the two lines will be the desired center of gravity. Fig. ao.
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( W v. 5 Copyright, 1897, by The Co
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Arithmetic, - CONTENTS Algebra, Log
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i ARITHMETIC. of tens. 1 + 8 + 7 +
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4 ARITHMETIC. and the difference (4
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ARITHMETIC. (c) 217 Multiply any tw
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8 ARITHMETIC. 72 in the dividend an
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10 ARITHMETIC. (70 X 50 X 24 X 20).
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12 ARITHMETIC, The 5 in the dividen
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14 ARITHMETIC. (22) (a) 576) 589824
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16 ARITHMETIC. (33) To reduce a fra
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18 ARITHMETIC. 3 3 (e) 15-r-7-43-=
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20 ARITHMETIC. (41) ,9| + 50i + 41+
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22 ARITHMETIC. (45) The man evident
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24 ARITHMETIC. • u s o e 3 2 o 93
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26 ARITHMETIC. {b) Here again the p
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28 ARITHMETIC. 64) 1.000000(. 01562
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30 ARITHMETIC. (66) In subtraction
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38 ARITHMETIC. (6) .875 — 5-=? Re
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84 ARITHMETIC. {c) First perform th
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36 ARITHMETIC. Reducing 387 387 to
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38 ARITHMETIC. nominator of the fra
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40 ARITHMETIC. (d) Base = percentag
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42 ARITHMETIC. Another method of so
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44 ARITHMETIC. (89) Here we have gi
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46 ARITHMETIC. 24 ) 13750 gr. 20 )
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48 ARITHMETIC. (98) Reduce the grai
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50 ARITHMETIC. contained times in 3
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gal.
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54 ARITHMETIC. (108) In multiplicat
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56 ARITHMETIC. Since there are 24 g
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58 ARITHMETIC. There are 100 lb. in
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60 ARITHMETIC. 62 is contained in 1
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63 ARITHMETIC. (121) (a) 106' = 106
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64 ARITHMETIC. (^) .4044* = .4044 X
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6G ARITHMETIC. Since there are 2 de
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68 ARITHMETIC. (128) {a) .0133' =.0
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70 ARITHMETIC (130^ (a) 1 1 20 _8 2
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72 ARITHMETIC. in the root. Write i
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74 ARITHMETIC. (^) 9 -/QO.OO'OO'OO
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76 ARITHMETIC. correction. This, mu
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78 ARITHMETIC. found by division sh
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80 ARITHMETIC. (137) {a) 1 1 f .0 6
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82 ARITHMETIC. (138^ {a) In this ex
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84 ARITHMETIC. (^)
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86 ARITHMETIC. {b) f 6 = VTa 2 4/G.
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88 8 8 ARITHMETIC.
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90 ARITHMETIC. 40,000 144)40000.0(2
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92 ARITHMETIC. (163) 2 ft. 5 in. =
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94 ARITHMETIC. (164) Taking the tim
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96 ALGEBRA. (171) See Arts. 352 and
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98 ALGEBRA. In this case, where we
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100 ALGEBRA. By Art. 482, the signs
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102 ALGEBRA. (189) Applying the met
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104 ALGEBRA. (196) {a) ^+_;/ + ^-(^
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106 ALGEBRA- (201 ) The subtraction
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108 ALGEBRA. Canceling the factors
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110 ALGEBRA. (208) (a) Writing the
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112 ALGEBRA. 20j^(4^+5)-12.r(3:r-7)
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ALGEBRA. (QUESTIONS 218-257.) (218)
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ALGEBRA. 117 Clearing of fractions,
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ALGEBRA. 119 Transposing, — A:X*
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Completing the square, ALGEBRA. 131
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Extracting ALGEBRA. 123
Page 137 and 138: (d) Completing the square, Extracti
Page 139 and 140: ALGEBRA. 127 (238) (a) i/| by Art.
Page 141 and 142: (242) ALGEBRA. 139 Let X = the whol
Page 143 and 144: (246) Then,-^ X ALGEBRA. 131 Let X
Page 145 and 146: ALGEBRA. 133 y+5-{x-o) = 6. (1) But
Page 147 and 148: ALGEBRA. 136 (266) Let X — the nu
Page 149 and 150: LOGARITHMS. (QUESTIONS 258-272.) (2
Page 151 and 152: l^OGARITHMS. 139 .6602 -3 — 1.980
Page 153 and 154: LOGARITHMS. 141 {l>) .76'"._ Log .7
Page 155: LOGARITHMS. 143 (271) Substituting
Page 158 and 159: 140 GEOMETRY AND TRIGONOMETRY. in t
Page 160 and 161: 148 GEOMETRY AND TRIGONOMETRY. 3 (2
Page 162 and 163: 150 GEOMETRY AND TRIGONOMETRY. (302
Page 166 and 167: 154 GEOMETRY AND TRIGONOMETRY. draw
Page 170 and 171: 158 GEOMETRY AND TRIGONOMETRY. {d)
Page 176 and 177: 1G4 GEOMETRY AND TRIGONOMETRY. (354
Page 178 and 179: 166 ELEMENTARY MECHANICS. per min.
Page 180 and 181: 168 ELEMENTARY MECHANICS. replaced,
Page 182 and 183: 170 ELEMENTARY MECHANICS. (384) (a)
Page 184 and 185: 172 ELEMENTARY MECHANICS. (389) See
Page 186 and 187: 174 ELEMENTARY MECHANICS. (398) 1 h
Page 192 and 193: 180 ELEMENTARY MECHANICS. a distanc
Page 196 and 197: 184 ELEMENTARY MECHANICS. (d) Using
Page 198 and 199: 186 ELEMENTARY MECHANICS. (452) (a)
Page 200 and 201: 188 HYDROMECHANICS. (457) (a) Area
Page 202 and 203: 190 HYDROMECHANICS. Pressure due to
Page 204 and 205: 192 HYDROMECHANICS. (47 1 ) (a) 36
Page 206 and 207: 194 HYDROMECHANICS. 5' X 7854 (479)
Page 208 and 209: 196 HYDROMECHANICS. (d) See Art. 10
Page 210 and 211: 198 HYDROMECHANICS. Pressure per sq
Page 212 and 213: aOO HYDROMECHANICS. For z;„ = 4,/
Page 214 and 215: 202 PNEUMATICS. (509) Substituting
Page 216 and 217: 204 PNEUMATICS. (519) 8.47 = origin
Page 218 and 219: 206 PNEUMATICS. (537) (a) 30 — 17
Page 220 and 221: 208 PNE-aMATlCS. (548) CO' — 50'
Page 222 and 223: 210 STRENGTH OF MATERIALS. P- p-^^.
Page 224 and 225: 212 STRENGTH OF MATERIALS. Since 40
Page 226 and 227: 214 STRENGTH OF MATERIALS. drawn. P
Page 228 and 229: 21G STRENGTH OF MATERIALS. c \d of
Page 230 and 231: 218 STRENGTH OF MATERIALS. n o. I//
Page 232 and 233: 220 STRENGTH OF MATERIALS. Substitu
Page 234 and 235: 222 STRENGTH OF MATERIALS. (589) Su
Page 236 and 237: 224 STRENGTH OF MATERIALS. (597) {a
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226 STRENGTH OF MATERIALS. (d) In t
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228 STRENGTH OF MATERIALS. (604) Us
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230 STRENGTH OP MATERIALS. (609) Th
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232 STRENGTH OF MATERIALS. moments
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234 SURVEYING. adjacent sides of th
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236 SURVEYING. (622) 1st. A B in Fi
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238 SURVEYING. true bearing IS the
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240 SURVEYING. A B, as the bearing
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Un SURVEYING. an angle of 15° 10'
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244 SURVEYING. in dotted lines. In
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246 SURVEYING. table of Radii and D
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248 SURVEYING. ^^^ = 1.875'. The de
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. (690) 250 SURVEYING. sight to the
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252 SURVEYING. and including that a
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254 SURVEYING. horizontal lines 1 f
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(706) LAND SURVEYING (QUESTIONS 706
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LAND SURVEYING. 259 ture of A B is
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LAND SURVEYING. 261 -{-, in the col
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LAND SURVEYING. 263 is +8.86 chains
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a a *• o « .i Q a V Q + • hJ *
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LAND SURVEYING. 2G7
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RAILROAD LOCATION. (756) (QUESTIONS
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RAILROAD LOCATION. 271 second curve
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RAILROAD LOCATION. 273 in which;!'
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RAILROAD LOCATION. 275 Whence, we h
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RAILROAD LOCATION. 277 4.0827 ft.,
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point so determined by RAILROAD LOC
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282 RAILROAD CONSTRUCTION. (818) Th
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884 RAILROAD CONSTRUCTION. (833) Ap
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286 RAILROAD CONSTRUCTION. (859) Fi
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288 RAILROAD CONSTRUCTION. (864) (8
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RAILROAD CONSTRUCTION. (QUESTIONS 8
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RAILROAD CONSTRUCTION. 293 (896) Se
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RAILROAD CONSTRUCTION. 295 (a) The
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RAILROAD CONSTRUCTION. 207 (939) Se
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300 TRACK WORK. (962) (963) (964) (
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302 TRACK WORK. (994) See Art. 1687
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304 TRACK WORK. (1008) 8 ft. G in.
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306 RAILROAD STRUCTURES. (1039) See
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308 RAILROAD STRUCTURES. (1060) Fro
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3," ^ >;> :3 3>32> ^ >:> J> Oi?^ :>
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UNIVERSrTY OF ILLINOIS-URBANA 3 011
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