\fdO'^ - Old Forge Coal Mines

162 GEOMETRY AND TRIGONOMETRY.
(348) Area of room = 15 X 18 or 270 square feet.
One yard of carpet 27 inches wide will cover 3 X 2 j (27
1 3
inches = 2j ft.) = 6- sq. ft. To cover 270 sq. ft., it will
V , 270 ,^ , .
take -j7^, or 40 yards.
bf
Ans.
(349) Area of ceiling = 16 X 20 = 320 square feet.
Area of end walls = 2(16 X 11) = 352 square feet.
Area of side walls = 2(20 x 11) = 440 square feet.
Total area = 1,112 square feet.
From the above number of square feet, the following
deductions are to be made :
Windows = 4(7 X 4) = 112 square feet.
Doors = 3(9 X 4) = 108 square feet.
Baseboard less the width of the three doors
equals (72' - 12') x ^^ = 30 square feet.
Total No. of feet to be deducted = 250 square feet.
Number of square feet to be plastered, then, equals 1,112
7
— 250, or 862 square feet, or 95^^ square yards. Ans.
7 10
(350) Given A B = &- inches, and OB=OA=t^ oi
6 inches, Fig. 17,
Fig 17.
to find the area of the sector.
Area of circle = 10' X .7854 = 78.54
square inches.
Sin^ OC = AC 6| = .6875 ;
0A~ 5
therefore, A O C = 43° 26'.
AOB=2xAOC=2x43°26' =
86° 52':= 86. 8666°.
86.8666
360
X 78. 54 ~ 1 8. 95 square inches.
An&