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\fdO'^ - Old Forge Coal Mines

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128 ALGEBRA.<br />

(tx X<br />

(r) am — b 7- H—— = 0, when cleared of fractions =<br />

^ ' am<br />

Transposing,<br />

abm^ — b'^m — amx -|- ^jr = 0.<br />

*<br />

bx — amx = b*m — abm*.<br />

Factoring, {b — am)x = bm{b — am) ;<br />

bm(b — .<br />

, am) ,<br />

whence, x = — -rr r^ = bm. Ans.<br />

{b — am)<br />

(240) ;r+j = 13. (1)<br />

xf = 36. (2)<br />

Squaring (1) we have<br />

;r» + 2xy+y = 169. (3)<br />

Multiplying (2) by 4, 4,ry = 144. (4)<br />

Subtracting (4) from (3),<br />

x'-2xy-i-y = 25. (6)<br />

Extracting the square root of (5),<br />

x-y=±5. (6)<br />

Adding (6) and (1),<br />

Substituting the value of x in (1),<br />

%r = 18 or 8,<br />

,r = 9 or 4. Ans.<br />

9+J' = 13,<br />

or 4+7=13;<br />

whence, 7=4,i ^^^<br />

or z=<br />

jf 9. i<br />

(241) x'-y = 98. (1)<br />

x-j = 2. (2)<br />

From •<br />

(2),<br />

x = 2-\-j'. {3)<br />

Substituting the value of x in (1),<br />

8 + 12j + 6y +y -y = 98.<br />

Combining and transposing,<br />

ey + 12j = 90.<br />

y -f 2^^ = 15.<br />

^ + 2^^+ 1 = 15 + 1 = 16.<br />

7+l=±4.<br />

J = 3, or — 5. Ans.<br />

Substituting the value of j in (3), x = 5, or — 3. Ans.

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