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AP Chemistry-midterm review - Quia

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a. Mg > Be > Ca > K > Cs<br />

b. Be > Mg > Ca > K > Cs<br />

c. Cs > K > Ca > Be > Mg<br />

d. Ca > Mg > Be > Cs > K<br />

e. Ca > Mg > Be > K > Cs<br />

____ 153. Arrange the following elements in order of increasing values of electron affinity, i.e., from most negative to<br />

least negative. (Note: None of these elements is an exception to the general trends of electron affinities.)<br />

Cl, Se, S, Cs, Rb, Te<br />

a. Cl < S < Se < Rb < Te < Cs<br />

b. Cl > Te > Se > S > Rb > Cs<br />

c. Cl > Se > S > Te > Rb > Cs<br />

d. Cl < S < Se < Te < Cs < Rb<br />

e. Cl < S < Se < Te < Rb < Cs<br />

____ 154. Which ion has the smallest radius?<br />

a. As 3-<br />

b. Se 2-<br />

c. Br -<br />

d. Rb +<br />

e. Sr 2+<br />

____ 155. Which element has the lowest electronegativity?<br />

a. Mg<br />

b. Na<br />

c. Rb<br />

d. Y<br />

e. Sc<br />

____ 156. Which comparison of electronegativities is not correct?<br />

a. Br > Se<br />

b. K > Mg<br />

c. O > S<br />

d. N > Be<br />

e. I > Ba<br />

____ 157. Which of the following responses lists only the ionic hydrides?<br />

I. LiH<br />

II. B2H6<br />

III. GeH4<br />

IV. HCl<br />

V. BaH2<br />

a. I<br />

b. I, V<br />

c. II, III<br />

d. II, III, IV<br />

e. I, II, V

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