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Advanced Package Training Scaffolding 2011.1 - Scia-Software GbR

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86<br />

<strong>Advanced</strong> <strong>Training</strong><br />

In our example the structure was unclad. We will take a look at the force parallel to the façade, so cf =<br />

1,3.<br />

The site coefficient cs :<br />

Cladding condition of the<br />

system configuration<br />

Site coefficient<br />

Normal to the façade Parallel to the façade<br />

Unclad 0,75 1,0<br />

Clad 1,0 1,0<br />

NOTE: The values for the site coefficients correspond to a façade with a solidity ratio ϕB= 0,4; see also EN12811-1.<br />

For an unclad structure, the wind parallel to the façade, results in cs = 1,0.<br />

For each beam the force can be calculated as a line force as shown below:<br />

<br />

= ∙ ∙ ∙ <br />

<br />

= 1,0 ∙ 0,0483 ∙ 1,3 ∙ 870 <br />

= 54,6 = 0,055<br />

<br />

This load is applied on the beams shown below (the toeboards are not taken into account, because the<br />

force coefficient is only available for tube profiles):<br />

So the total force inserted is:<br />

0,055 kN/m x<br />

[(2+2x0,5)x 2,57m<br />

+ (2x0,5)x 2m +3,257]<br />

= 0,055 kN/m (12,97m)<br />

= 0,71 kN<br />

In the calculation of “6. Load cases”, a load of 0,17kN/m² has been taken into account. This value<br />

multiplied with the surface (= 2m x 2,57m) gives a total force of 0,68kN.<br />

So the two option results in a value close to each other.

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