Advanced Package Training Scaffolding 2011.1 - Scia-Software GbR

Buckling Shape [-]
A polynomial has the advantage that the second derivative can easily be calculated.
η
-50
-100
-150
-200
-250
-300
-350
-400
⇒ cr
−12
4
−8
3
−6
2
−1
−2
= −2,
117E
x + 2,
117E
x − 7,
240E
x − 2,
284E
x − 7,
622E
''
⇒ η cr , max
−11
2
−7
−5
= −2,540
E x + 1,270 E x − 1,448 E
Calculation of e0
Buckling Shape
0
0 500 1000 1500 2000 2500 3000 3500 4000 4500 5000
y = -2,117E-12x 4 + 2,117E-08x 3 - 7,240E-06x 2 - 2,284E-01x - 7,622E-02
Length [mm]
NRk = f × = 235 N
y A
× 5380mm²
=
mm²
M Rk
3
= f × = 235 N
y Wpl
× 628400mm
=
mm²
λ =
NRk
Ncr
= 1264300N
= 0,43
6885280N
α = 0,21 for buckling curve a
χ
1
2
0,
51
+ α λ − 0.
2 + λ + 0,
51
+ α λ − 0.
2
55
1264300 N
147674000 Nmm (class 2)
[ ( ) ( ) ] ( [ ( ) ( ) ] ) ( ) 2
2 2
+ λ − λ
= =0,945
Scaffolding
These intermediate results can be verified through SCIA ENGINEER when performing a Steel Code
Check on the column: