Physical Science P1 Additional Exemplar Memo ... - SmartLearner

Physical Sciences/Fisiese Wetenskappe/P1/V1 6
DoE/Exemplar/Model 2008
NSC/NSS – Memorandum
5.3.2 Velocities will be the same/Snelhede sal dieselfde wees.
Both X and Y experience the same displacement and
same acceleration. On its downward flight X has same
velocity as Y at a height of h.
2 2
Using v f = v i + 2aΔy
will thus give the same final velocity
for both.
Beide X en Y ondergaan dieselfde verplasing. en
ondervind dieselfde versnelling. . Op sy afwaarste vlug het
X dieselfde snelheid as Y op hoogte h. Deur gebruik te
2 2
maak van v f = v i + 2aΔy
sal beide dus dieselfde
eindsnelheid hê.
5.4 For X - upward as negative/Vir X - opwaarts as negatief:
2 2
= v + 2aΔy
= (2) 2 + 2(9,8)(50) = 31,37 m·s -1
v f i
vf = vi
+ a Δt
∴ 31,37 = 2 + 9,8 Δ t
∴ Δ t = 2,997 = 3 s
For/Vir Y:
Δ t = 3 – 1 = 2 s
1 2
Δ = v Δt
+ aΔt
y i 2
∴50 = vi(2) + 0,5(9,8)(2) 2
∴vi = 15,2 m·s -1 downward/afwaarts
OR/OF
For X - upward as negative/Vir X - opwaarts as negatief:
1 2
Δ = v Δt
+ aΔt
y i 2
1 2 2
50 = 2 Δ t + (9,8) Δ t ∴4,9 Δ t + 2 Δ t – 50 = 0
2
2
−b
± b − 4ac
− 2±
Δ t =
=
2a
∴ Δ t = 2,997 s = 3 s
For/Vir Y:
Δ t = 3 – 1 = 2 s
1 2
Δ = v Δt
+ aΔt
2
2
− 4(
4,
9)(
−50)
2(
4,
9)
y i 2
∴50 = vi(2) + 0,5(9,8)(2) 2
∴vi = 15,2 m·s -1 downward/afwaarts
[12.1.4]
[12.1.3]
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