BRAND NEW M Lit 27 AUG P2memo.pdf - sacai
BRAND NEW M Lit 27 AUG P2memo.pdf - sacai
BRAND NEW M Lit 27 AUG P2memo.pdf - sacai
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Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
MATHEMATICAL<br />
LITERACY PAPER 2<br />
Preparatory Examination 2012<br />
MEMORANDUM<br />
This memorandum consists of 9 pages<br />
Copyright Reserved Page 0
Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
NOTE<br />
Read the following instructions carefully:<br />
If a candidate answers a question TWICE, only mark the FIRST attempt.<br />
If a candidate has crossed out an attempt of a question and not redone the<br />
question, mark the crossed out version.<br />
Consistent accuracy applies in ALL aspects of the marking memorandum.<br />
Symbol Explanation Verduideliking<br />
M Method Metode<br />
MA Method with Accuracy Metode met akkuraatheid<br />
CA Consistent accuracy Deurlopende Akkuraatheid<br />
A Accuracy (Answer) Akkuraatheid / Andwoord<br />
C Conversion Omskakeling / Herleiding<br />
S Simplification Vereenvoudiging<br />
RT / RG / RM Reading from Table/Graph/Map Lees vanaf ‘n Tabel / Grafiek / Kaart<br />
F Choosing the correct formula Keuse van formule<br />
SF Substitution in formula Korrekte vervanging in ‘n formule<br />
O Opinion Opinie / voorbeeld<br />
R Rounding off / Reason Afronding / Rede<br />
P Penalty e.g. no units, ect Penalisering bv. Eenhede weggelaat<br />
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Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
QUESTION 1 [31 Marks]<br />
No Calculations / workings<br />
1.1.1 Basic Salary(A) = R 16 821,75 - R 800,00 √<br />
= R 16 021,75 √ (2)<br />
1.1.2 Annual basic salary(B) = R 16 021,75 x 12 √<br />
= R 192 261,00 √ (2)<br />
1.1.3 Total deductions (C) = R 2 091,86 + R 1 201,63 + R 546,00<br />
= R 3 839,49<br />
Net salary (D) = R 16 821,75 - R 3 839,49 √<br />
= R 12 982,26 √ (2)<br />
1.2.1 Yearly taxable income<br />
= R 28 800 + 25% of (amount above R 160 000) - tax rebates<br />
= R 28 800 + 25% x (R 201 861 - R 160 000) – R 11 440 √√√<br />
= R 28 800 + 0,25 x R 41 861 - R 11 440<br />
= R 28 800 + R 10 465,25 - R 11 440 √<br />
= R <strong>27</strong> 825,25 √<br />
Monthly income tax =<br />
√<br />
= R 2 318,77 √ (7)<br />
1.2.2 No, only R 2 091,86 tax was deducted instead of<br />
R 2 318,77√√ (2)<br />
1.3.1 R 4 999 = 114% √ OR 1,14 . = R 4 999 √<br />
= 1% = √<br />
R 43,8509 = 1% √<br />
R 4 385,09 = 100% √ = R 4 385,09 √ (3)<br />
1.3.2 On terms = R 500,00 + ( R 189,00 x 36 ) √<br />
= R 500,00 + R 6 804,00 √<br />
= R 7 304,00 √ (3)<br />
1.3.3 A = R 4 999,00 ( 1 - 0,2) 5 √√√<br />
= R 1 638,07 √ (5)<br />
1.4 Total area = (L x B) + (<br />
x<br />
= (50cm x 60cm) +<br />
x 3,14 x 30cm √√√<br />
= 300cm 2 + 1 413cm 2 √<br />
= 1 713cm 2 √ (5)<br />
Marks /<br />
commen<br />
Copyright Reserved Page 2<br />
tttts<br />
M: 1<br />
A: 1<br />
M: 1<br />
A: 1<br />
M: 1<br />
A: 1<br />
SF: 3<br />
S: 1<br />
A: 1<br />
M: 1<br />
A: 1<br />
A: 1<br />
R: 1<br />
M:2<br />
A: 1<br />
M: 1<br />
S: 1<br />
A: 1<br />
SF: 3<br />
A: 2<br />
SF: 3<br />
S: 1<br />
A: 1<br />
AS LEVEL<br />
12.1.1 2<br />
12.1.1 2<br />
12.1.1 2<br />
12.1.3 4<br />
12.1.3 4<br />
12.1.3 3<br />
12.1.1 2: 2 marks<br />
&<br />
3: 1 mark<br />
12.1.3 4<br />
12.3.3 3: 3 marks<br />
&<br />
4: 2 marks
Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
QUESTION 2 [25 Marks]<br />
NO Calculations Mark<br />
comment<br />
2.1 Veranda: 1,5m x 4m √√√ (3) A: 3<br />
2.2.1 Bathroom = 2,5m x 4m = 10m 2 √<br />
Kitchen = 3m x 4m = 12m 2 √<br />
Veranda = 1,5m x 4m = 6,0m 2 √<br />
Total area to be tiled = 6m 2 + 12m 2 + 10m 2<br />
2.2.2 28m 2 + 2m 2 = 30m 2 √<br />
√<br />
= 22 boxes of tiles √<br />
= 28m 2 √ (4)<br />
Cost of tiles = 22 boxes x R 169,95 / box √<br />
= R 3 738,90 √<br />
Yes Ms Olivier budget of R 3 800 is correct √ (6)<br />
2.3 Total area = 12m 2 + 16m 2 = 28m 2<br />
Cost for under carpet = 28m 2 x R 45,99 / m 2 √<br />
= R 1 287,72 √<br />
OR:<br />
Cost of carpets =28m 2 x R209,00/m 2 √ 28 (R209+R45,99)/<br />
= R 5 852,00 √ = R 7 139,72<br />
2.4<br />
Total cost for carpeting = R 7 139,72 √ (5)<br />
Total cost for fittings = R 3 999 + (3 x R 739) + R 789 √√√<br />
= R 3 999 + R 2 217 + R 789 √<br />
= R 7 005 √<br />
Yes ms Olivier can afford to put in the gas stove because<br />
she has R 995 left of R 8 000 √√ (7)<br />
AS LEVEL<br />
12.3.1 3<br />
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M: 3<br />
A: 1<br />
Adding:<br />
1<br />
M: 1<br />
A: 1<br />
Adding:<br />
1<br />
M: 1<br />
S: 1<br />
M: 1<br />
S: 1<br />
A: 1<br />
M: 3<br />
S: 1<br />
A: 1<br />
A: 1<br />
R: 1<br />
12.3.1 3<br />
12.3.1 4<br />
12.3.1 3<br />
12.1.1<br />
12.1.2<br />
4
Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
QUESTION 3 [34 Marks]<br />
No Calculations Mark<br />
comment<br />
3.1.1 C 2 √ OR (1) A: 1<br />
3.1.2 North Westerly √ (2)<br />
3.1.3 4cm represents 500m<br />
1cm : 125 m √<br />
15,5 cm as the crow fly √ OR<br />
(15,5 x 125)m √ (16 x 125)m<br />
= 1937,5 m = 2 000m<br />
2km √ = 2km (4)<br />
3.1.4 3cm x 3cm<br />
= 3 x 125m x 3 x 125m √<br />
= 375m x 375m √<br />
= 140 625m 2 √ (3)<br />
3.1.5 11 squares (2)<br />
3.1.6 11 x 140 625m 2 √<br />
= 1 546 875m 2 √<br />
= 1,546875km 2<br />
1,5km 2 √ (3)<br />
3.2.1 HIGHEST - 1956 √<br />
Difference: 500 - 150 √<br />
= 350 √ (3)<br />
3.2.2 1963; 1969; 1984; 1988 √√√√ (Allow ± 1 year) (4)<br />
3.2.3 1963 to 1969 and √√ (Allow ± 1 year)<br />
1984 to 1988 √√ (4)<br />
3.3.1 Windscreen wipers √ (1)<br />
3.3.2<br />
3.3.3<br />
x 1000 √<br />
= 100 √ (2)<br />
or 0,8 or 80% √ (1)<br />
3.3.4 Annexure A (4)<br />
AS LEVEL<br />
12.3.4 2<br />
A: 2 12.3.4 2<br />
S: 1<br />
(between<br />
15cm and<br />
16cm): 1<br />
M: 1<br />
A: 1<br />
12.3.2<br />
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M: 2<br />
A: 1<br />
12.3.2<br />
3<br />
3<br />
A: 2 12.3.1 3<br />
M: 1<br />
S: 1<br />
A:1<br />
A: 1<br />
M: 1<br />
A: 1<br />
12.3.2 3<br />
12.4.1 3<br />
A: 4 12.4.1 4<br />
A: 4 12.4.2 3: 2 marks<br />
&<br />
4: 2 marks<br />
A: 1 12.4.5 2<br />
M: 1<br />
A: 1<br />
12.4.5 2<br />
A: 1 12.4.5 2<br />
12.4.5 3
Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
QUESTION 4 [24 Marks]<br />
No Calculations Mark<br />
Comment<br />
4.1.1<br />
(a)<br />
False. At least 25 % of the learners who wrote the test from<br />
School A did not get any answers correct. √√ (2)<br />
(b) True. The median is 67%. This means that at least half the<br />
learners scored 67% or more. So, at least half the learners<br />
passed the test. √√ (2)<br />
(c) True. Range = maximum mark - minimum mark = 65 for<br />
both schools. √√ (2)<br />
(d) True. The median is 67%. This means that at least half the<br />
learners scored 67% or more. So, at least half of 180 (90<br />
learners) got 67%. √√ (2)<br />
(e) False. The 50 th percentile is the median. The median for<br />
School B is 67% and no learner from School A scored above<br />
65%. √√ (2)<br />
4.2(a) Histogram 4. The 1 st quartile is 0, which means that 50<br />
learners must got 0. √√√ (3)<br />
4.2(b) Histogram 2. The minimum mark at School B was 35. √√√(3)<br />
AS LEVEL<br />
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A: 1<br />
R: 1<br />
A: 1<br />
R: 1<br />
A: 1<br />
R: 1<br />
A: 1<br />
R: 1<br />
A: 1<br />
R: 1<br />
A: 1<br />
R: 2<br />
A: 1<br />
R: 2<br />
12.4.1 4<br />
12.4.1 4<br />
12.4.1 3<br />
12.4.1 4<br />
12.4.1 4<br />
12.4.3 4<br />
12.4.3 4<br />
4.3.1<br />
(a)<br />
B √√ (2) A: 2 12.2.2 2<br />
(b) C √√ (2) A: 2 12.2.2 2<br />
(c) D √√ (2)<br />
(d) A √√ (2)<br />
A: 2 12.2.2 2<br />
A: 2 12.2.2 2
Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
QUESTION 5 [24 Marks]<br />
No Calculations Mark<br />
comment<br />
5.1 Amount of postage (Method A) = R 24,36 + (4 x R 3,28) √√<br />
= R 37,48 √ (3)<br />
5.2 Cost per Courier = R 45 √ (1)<br />
5.3.1 C = 24,36 + 3,28(n-1) √√ (2)<br />
5.3.2 A = R 24,36 + (29 x R 3,28) = R 119,48 √√√<br />
B = R 45 + R 10 = R 55 √√<br />
C = R 45 + (R 2 x R 10) = R 65 √√ (7)<br />
5.3.3 Annexure B (7)<br />
5.3.4 Method B (Courier service) (1)<br />
5.3.5 Small parcels less than 7,5kg use method A √<br />
Parcels more than 8kg method B √√ (3)<br />
M: 2<br />
A: 1<br />
AS LEVEL<br />
12.1.1 3<br />
A: 1 12.1.1 2<br />
A: 2 12.2.3 3<br />
M: 4<br />
A: 3<br />
12.2.1 3<br />
12.2.4 3<br />
A: 2 12.2.2 4<br />
R: 3 12.2.4<br />
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4
Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
Question 6 [12 Marks]<br />
6.1.1<br />
6.1.2<br />
6.1.3<br />
6.2<br />
Between <strong>27</strong> July and 04 Augustus 2008 √√ (2)<br />
RG: 2 12.2.3 3<br />
The exchange rate was stable √√ (2) O: 2 12.2.3 3<br />
R 18 125,00 = $(<br />
) √√<br />
= $ 2 196,97 √<br />
= $ 2 197 , Yes he received the right<br />
amount √ (4)<br />
* As the Rand further weakens against the Dollar he<br />
would get more if he change his Dollars against the Rand √<br />
* As a frequent traveller to the US he would always need<br />
Dollars therefore rather keep it √√<br />
* It’s better not to change currencies, as he would have to<br />
spend money each time he changes, on bank charges √√<br />
OR 2 any logical answers (4)<br />
BLOOM’s TOXONOMY LO’s<br />
MA: 2<br />
CA: 1<br />
R: 1<br />
O: 2<br />
O: 2<br />
Any 2<br />
reasons<br />
Level 1 - 0 marks - 0% LO 1 - 41 marks - <strong>27</strong>%<br />
Level 2 - 24 marks - 16% LO 2 - 36 Marks - 24%<br />
Level 3 - 64 marks - 43% LO 3 - 38 Marks - 25%<br />
Level 4 - 62marks - 41% LO 4 - 35 Marks - 23%<br />
TOTAL : 150 marks<br />
12.1.3 4<br />
12.2.3 4<br />
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Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
Question 3.3.4 - Tree diagram<br />
First car checked Second car checked<br />
(<br />
Faulty brakes<br />
Good brakes<br />
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(<br />
(<br />
(<br />
)Faulty brakes √<br />
Good brakes √<br />
Faulty brakes √<br />
) Good brakes √
Mathematical <strong>Lit</strong>eracy P 2 Memorandum September 2012<br />
Question 5.3.2<br />
`<br />
Cost (R)<br />
200<br />
180<br />
160<br />
140<br />
120<br />
100<br />
80<br />
60<br />
40<br />
20<br />
Three marks for Method A √ √ √<br />
Three marks for Method B √ √ √<br />
Relationship between the cost of sending<br />
a parcel and the number of kilogram per parcel<br />
5 10 15 20 25 30 35 40<br />
Number of kilograms (kg)<br />
Option A<br />
Option B<br />
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