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ENTANGLEMENT OF GAUSSIAN STATES Gerardo Adesso

ENTANGLEMENT OF GAUSSIAN STATES Gerardo Adesso

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70 4. Two-mode entanglement<br />

0.4<br />

S3 0.2<br />

0<br />

0<br />

0.25<br />

0.5<br />

Μ1<br />

0.75<br />

(a)<br />

1<br />

0.25<br />

0<br />

0.75<br />

0.5<br />

Μ2 Μ2<br />

0.3<br />

0.2<br />

S4<br />

0.1<br />

0<br />

0<br />

0.25<br />

0.5<br />

Μ1<br />

0.75<br />

(b)<br />

1<br />

0.25<br />

0<br />

0.75<br />

0.5<br />

Μ2 Μ2<br />

Figure 4.3. Plot of the nodal surface which solves the equation κp = 0 with<br />

κp defined by Eq. (4.48), for (a) p = 3 and (b) p = 4. The entanglement<br />

of Gaussian states that lie on the leaf–shaped surfaces is fully quantified in<br />

terms of the marginal purities and the global generalized entropy (a) S3 or (b)<br />

S4. The equations of the surfaces in the space Ep ≡ {µ1, µ2, Sp} are given by<br />

Eqs. (4.51–4.53).<br />

Sp for a generic p. Using Maxwell’s relations, we can write<br />

κp ≡ ∂(2˜ν2 −)<br />

∂∆<br />

<br />

<br />

<br />

Sp<br />

= ∂(2˜ν2 −)<br />

∂∆<br />

<br />

<br />

<br />

R<br />

− ∂(2˜ν2 −)<br />

∂R<br />

<br />

<br />

<br />

∆<br />

· ∂Sp/∂∆| R . (4.47)<br />

∂Sp/∂R| ∆<br />

Clearly, for κp > 0 GMEMS and GLEMS retain their usual interpretation, whereas<br />

for κp < 0 they exchange their role. On the node κp = 0 GMEMS and GLEMS<br />

share the same entanglement, i.e. the entanglement of all Gaussian states at κp = 0<br />

is fully determined by the global and marginal p−entropies alone, and does not<br />

depend any more on ∆. Such nodes also exist in the case p ≤ 2 in two limiting<br />

instances: in the special case of GMEMMS (states with maximal global purity at<br />

fixed marginals) and in the limit of zero marginal purities. We will now show that,<br />

besides these two asymptotic behaviors, a nontrivial node appears for all p > 2,<br />

implying that on the two sides of the node GMEMS and GLEMS indeed exhibit<br />

opposite behaviors. Because of Eq. (4.42), κp can be written in the following form<br />

κp = κ2 −<br />

R<br />

˜∆ 2 − R 2<br />

with Np and Dp defined by Eq. (4.44) and<br />

˜∆ = −∆ + 2<br />

µ 2 +<br />

1<br />

2<br />

µ 2 2<br />

,<br />

κ2 =<br />

˜∆<br />

−1 + ,<br />

˜∆ 2 − R2 Np(∆, R)<br />

, (4.48)<br />

Dp(∆, R)<br />

The quantity κp in Eq. (4.48) is a function of p, R, ∆, and of the marginals;<br />

since we are looking for the node (where the entanglement is independent of ∆), we<br />

can investigate the existence of a nontrivial solution to the equation κp = 0 fixing<br />

any value of ∆. Let us choose ∆ = 1 + R 2 /4 that saturates the uncertainty relation

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