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1. 6<br />

2. 90°; 18°<br />

3. 45°<br />

4. See flowchart below.<br />

5. See flowchart below.<br />

6. 1<br />

Isosceles ABC<br />

with AC BC<br />

and CD bisects<br />

C<br />

Given<br />

3<br />

AD BD<br />

CPCTC<br />

4. (Lesson 4.8)<br />

LESSON 4.8<br />

2<br />

ADC BDC<br />

Conjecture A<br />

(Exercise 4)<br />

4<br />

CD is a median<br />

Def. of median<br />

<br />

1<br />

CD is the bisector of C<br />

2 ? 1 2<br />

Given Definition of<br />

angle bisector<br />

5. (Lesson 4.8)<br />

1 ABC is isosceles with<br />

AC BC, and CD is<br />

the bisector of C<br />

Given<br />

3<br />

4<br />

ABC is isosceles<br />

with AC BC<br />

Given<br />

CD CD<br />

Same segment<br />

2 ADC BDC<br />

Conjecture A<br />

3<br />

1 and 2 form<br />

a linear pair<br />

Definition of<br />

linear pair<br />

7.<br />

1<br />

AC BC<br />

2<br />

CD CD<br />

3<br />

D is<br />

Given Same segment<br />

midpoint<br />

of AB<br />

Given<br />

5<br />

ADC BDC<br />

4<br />

AD BD<br />

SSS<br />

Def. of midpoint<br />

6 ACD DCB<br />

CPCTC<br />

8<br />

CD is altitude<br />

of ABC<br />

Conjecture B<br />

(Exercise 5)<br />

7 CD is angle<br />

bisector of ACB<br />

Def. of angle bisector<br />

9<br />

CD AB<br />

Def. of altitude<br />

8. Yes. First show that the three exterior triangles<br />

are congruent by SAS.<br />

4 1 2<br />

?<br />

<br />

CPCTC<br />

5 ADC BDC<br />

?<br />

<br />

5 1 and 2 are<br />

supplementary<br />

Linear Pair<br />

Conjecture<br />

SAS<br />

7<br />

Definition of<br />

perpendicular<br />

CD is an altitude<br />

6 1 and 2 are<br />

right angles<br />

8<br />

Congruent<br />

supplementary<br />

angles are 90<br />

CD AB <br />

?<br />

<br />

?<br />

<br />

Definition of<br />

altitude<br />

ANSWERS TO EXERCISES 57<br />

<strong>Answers</strong> to Exercises

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