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Geo_Book_Answers

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<strong>Answers</strong> to Exercises<br />

LESSON 2.5<br />

1. a 60°, b 120°, c 120°<br />

2. a 90°, b 90°, c 50°<br />

3. a 77°, b 52°, c 77°, d 51°<br />

4. a 60°, b c 120°, d f 115°, e 65°,<br />

g i 125°, h 55°<br />

5. a 90°, b 163°, c 17°, d 110°, e 70°<br />

6. The measures of the linear pair of angles add up<br />

to 170°, not 180°.<br />

7. The angles at which he should cut measure 45°.<br />

8. Greatest: 120°. Smallest: 60°. One possible<br />

explanation: The tree is perpendicular to the<br />

horizontal. The angle of the hill measures 30°.<br />

The smaller angle and the angle between the hill<br />

and the horizontal form a pair of complementary<br />

angles, so the smaller angle equals 90° 30° 60°.<br />

The smaller angle and larger angle form a linear<br />

pair, so the larger angle equals 180° 60° 120°.<br />

9. The converse is not true. ; sample counterexample:<br />

A<br />

55<br />

125<br />

B<br />

10. each must be a right angle<br />

11. Let the measures of the congruent angles be x.<br />

They are supplementary, so x x 180°, 2x 180°,<br />

x 90°. Thus each angle is a right angle.<br />

12. The ratio is 1. The ratio does not change as<br />

long as the lines don’t coincide. Because the<br />

demonstration does not explain why, it is not<br />

a proof.<br />

13. P<br />

14.<br />

3<br />

A<br />

5<br />

28 ANSWERS TO EXERCISES<br />

T<br />

22. (Lesson 2.5)<br />

15.<br />

16.<br />

17.<br />

6<br />

18. Possible answer: All the cards look exactly as<br />

they did, so it must be the 4 of diamonds, because<br />

it has rotational symmetry while the others do not.<br />

19. 22.5°<br />

20.<br />

21. C n H 2n<br />

H H<br />

H C C<br />

H H<br />

22. See table below.<br />

23. handshake problem: n(n 1)<br />

2<br />

pieces of string<br />

24. 3160 intersections<br />

25. n(n 2)<br />

<br />

2 yields 760 handshakes.<br />

26. 21; 252<br />

27. n(n 3)<br />

2<br />

3 4<br />

H<br />

C<br />

H<br />

H<br />

C<br />

H<br />

H<br />

C<br />

H<br />

80( 79)<br />

; <br />

2<br />

560; there are 35 vertices.<br />

28. M is the midpoint of AY;deductive.<br />

Rectangle 1 2 3 4 5 6 … n … 200<br />

Perimeter of rectangle 10 14 18 22 26 30 … 4n 6 … 806<br />

O<br />

A<br />

T<br />

H<br />

C<br />

H<br />

C<br />

H<br />

H<br />

C<br />

H<br />

3160<br />

Number of squares 6 12 20 30 42 56 … … 40,602<br />

(n 1)(n 2)

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