Geo_Book_Answers
Geo_Book_Answers
Geo_Book_Answers
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<strong>Answers</strong> to Exercises<br />
LESSON 2.5<br />
1. a 60°, b 120°, c 120°<br />
2. a 90°, b 90°, c 50°<br />
3. a 77°, b 52°, c 77°, d 51°<br />
4. a 60°, b c 120°, d f 115°, e 65°,<br />
g i 125°, h 55°<br />
5. a 90°, b 163°, c 17°, d 110°, e 70°<br />
6. The measures of the linear pair of angles add up<br />
to 170°, not 180°.<br />
7. The angles at which he should cut measure 45°.<br />
8. Greatest: 120°. Smallest: 60°. One possible<br />
explanation: The tree is perpendicular to the<br />
horizontal. The angle of the hill measures 30°.<br />
The smaller angle and the angle between the hill<br />
and the horizontal form a pair of complementary<br />
angles, so the smaller angle equals 90° 30° 60°.<br />
The smaller angle and larger angle form a linear<br />
pair, so the larger angle equals 180° 60° 120°.<br />
9. The converse is not true. ; sample counterexample:<br />
A<br />
55<br />
125<br />
B<br />
10. each must be a right angle<br />
11. Let the measures of the congruent angles be x.<br />
They are supplementary, so x x 180°, 2x 180°,<br />
x 90°. Thus each angle is a right angle.<br />
12. The ratio is 1. The ratio does not change as<br />
long as the lines don’t coincide. Because the<br />
demonstration does not explain why, it is not<br />
a proof.<br />
13. P<br />
14.<br />
3<br />
A<br />
5<br />
28 ANSWERS TO EXERCISES<br />
T<br />
22. (Lesson 2.5)<br />
15.<br />
16.<br />
17.<br />
6<br />
18. Possible answer: All the cards look exactly as<br />
they did, so it must be the 4 of diamonds, because<br />
it has rotational symmetry while the others do not.<br />
19. 22.5°<br />
20.<br />
21. C n H 2n<br />
H H<br />
H C C<br />
H H<br />
22. See table below.<br />
23. handshake problem: n(n 1)<br />
2<br />
pieces of string<br />
24. 3160 intersections<br />
25. n(n 2)<br />
<br />
2 yields 760 handshakes.<br />
26. 21; 252<br />
27. n(n 3)<br />
2<br />
3 4<br />
H<br />
C<br />
H<br />
H<br />
C<br />
H<br />
H<br />
C<br />
H<br />
80( 79)<br />
; <br />
2<br />
560; there are 35 vertices.<br />
28. M is the midpoint of AY;deductive.<br />
Rectangle 1 2 3 4 5 6 … n … 200<br />
Perimeter of rectangle 10 14 18 22 26 30 … 4n 6 … 806<br />
O<br />
A<br />
T<br />
H<br />
C<br />
H<br />
C<br />
H<br />
H<br />
C<br />
H<br />
3160<br />
Number of squares 6 12 20 30 42 56 … … 40,602<br />
(n 1)(n 2)